Frequency of Reflected Underwater Sound Wave

Click For Summary
SUMMARY

The discussion centers on calculating the frequency difference between sonar waves emitted by a ship and those reflected off a whale moving towards the ship. The ship's sonar operates at 18.0 kHz, with sound traveling at 1482 m/s in water at 20°C. The initial calculation yielded a frequency shift of 60 Hz, but the correct shift is 120 Hz due to the Doppler effect being applied twice—once when the whale acts as a listener and again when it acts as a source. This highlights the importance of correctly applying the Doppler effect in two-step scenarios.

PREREQUISITES
  • Doppler Effect in sound waves
  • Basic principles of wave frequency and speed
  • Understanding of relative motion in physics
  • Mathematical manipulation of equations
NEXT STEPS
  • Study the Doppler Effect in detail, focusing on sound waves
  • Learn about the mathematical derivation of frequency shifts in moving sources and observers
  • Explore applications of sonar technology in marine biology
  • Investigate the impact of temperature on sound speed in water
USEFUL FOR

Students in physics, marine biologists utilizing sonar technology, and anyone interested in the principles of wave mechanics and the Doppler effect.

betamu
Messages
12
Reaction score
3

Homework Statement


The sound source of a ship’s sonar system operates at
a frequency of 18.0 kHz. The speed of sound in water (assumed
to be at a uniform 20°C) is 1482 m/s. What is the difference
in frequency between the directly radiated waves and the waves
reflected from a whale traveling directly toward the ship at
4.95 m/s ? The ship is at rest in the water.

Homework Equations


fship = (v+vship/v+vwhale)fwhale

The Attempt at a Solution


To find the frequency of the reflected waves, I used the above equation with vship=0 and vwhale=-4.95m/s. Found the reflected frequency to be 18060.32Hz, which means a 60Hz difference. My textbook says it should be double that, 120Hz.
 
Physics news on Phys.org
What you have determined is the frequency shift experienced by the whale if the whale were the receiver. Bouncing off the whale and returning to the ship doubles the effect. It’s as if the whale is now an emitter at the Doppler shifted frequency and the ship hears that frequency Doppler shifted again

By the way, I think in trying to do it in one step you’ve put f0 on the wrong side of the equation
 
  • Like
Likes   Reactions: CWatters
Step 1: Whale is listener and listener is moving
Step 2: Whale is source and source is moving.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
1K
Replies
20
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 19 ·
Replies
19
Views
5K
  • · Replies 33 ·
2
Replies
33
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K