Frequency for resonance to occur

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Homework Help Overview

The discussion revolves around the resonance frequencies of sound waves in a pipe with a speaker and a piston. The original poster presents a scenario involving two resonance points and seeks to determine the frequency at which resonance occurs again after increasing the frequency slightly. Key parameters include the end correction, wavelength, and speed of sound.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between frequency, wavelength, and the speed of sound, questioning how changes in these parameters affect resonance. There is discussion about the implications of room size on sound speed and the use of end correction in calculations.

Discussion Status

The conversation is ongoing, with participants sharing calculations and questioning the accuracy of their results. Some have provided insights into the relationships between frequency and wavelength, while others are clarifying the conditions under which resonance occurs. There is no explicit consensus yet on the correct frequency for the third resonance.

Contextual Notes

Participants note discrepancies in calculated values and the original problem statement, leading to discussions about potential errors and assumptions in their calculations. The end correction and its impact on wavelength are also under consideration.

  • #31
Helly123 said:
Maybe
##L_3(\lambda')## = ##\frac{5}{4}\lambda## - ε
0.151 = ##\frac{5}{4}\lambda## - 0.008
##\frac{5}{4}\lambda## = 0.159
##\lambda## = 0.2 * 4/5 = 0.16 = 0.2 m

That way, frequency = 340/0.2 = 1700 Hz
Here is what I think happened. Whoever made the answer key thought ##L_3(λ') = \frac 4 5 λ'-ε##. That would give 1710hz for the frequency. Rounding to 2 significant digits, it would be 1700hz.
 
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  • #32
tnich said:
Here is what I think happened. Whoever made the answer key thought ##L_3(λ') = \frac 4 5 λ'-ε##. That would give 1710hz for the frequency. Rounding to 2 significant digits, it would be 1700hz.
How can you assume the 1710 Hz? How to get that result?
 
  • #33
Helly123 said:
How can you assume the 1710 Hz? How to get that result?
Using ##\frac 4 5 λ## instead of ##\frac 5 4 λ##, but that would not be correct.
 
  • #34
Ok thanks
 

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