Frequency Spectrum of a Vibrating String

  • Context:
  • Thread starter Thread starter Dustinsfl
  • Start date Start date
  • Tags Tags
    Concept Frequency
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
8 replies · 3K views
Dustinsfl
Messages
2,217
Reaction score
5
Given $\sin\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right]$.

The period is $\tau = \frac{2L}{c\left(n + \frac{1}{2}\right)}$ so the frequency is $\frac{1}{\tau}$, correct?
 
Last edited:
Physics news on Phys.org
Yes:

$\displaystyle f=\frac{1}{\tau}$
 
MarkFL said:
Yes:

$\displaystyle f=\frac{1}{\tau}$

Is the period I obtained correct? Is that the yes or is the yes it is the reciprocal?
 
If you have a function $\sin(kt)$, find the period $\tau$ by setting $k\tau=2\pi$.
 
Sorry for being vague. :)

I agree with the period you found and with the relationship between frequency and period that you stated.

$\displaystyle \tau=\frac{2\pi}{\omega}$

In your case $\displaystyle \omega=\frac{\pi e}{L}\left(n+\frac{1}{2} \right)$

And so:

$\displaystyle \tau=\frac{2\pi}{ \frac{\pi e}{L} \left(n+ \frac{1}{2} \right)}= \frac{2L}{e\left(n+\frac{1}{2} \right)}$
 
Ackbach said:
If you have a function $\sin(kt)$, find the period $\tau$ by setting $k\tau=2\pi$.
Is there a difference between frequency and natural frequency (eigenfrequencies)?
 
dwsmith said:
Is there a difference between frequency and natural frequency (eigenfrequencies)?

The term "natural frequency" refers to resonance. So if you have a forced mass-spring system, e.g., and you tune the forcing function to the same frequency as a term in the homogeneous solution, you end up with unstable behavior.

The term "frequency" just refers to what's going on in this thread.

There's also the term "angular frequency", which is represented by $\omega=2\pi f$.

Hope that's as clear as mud.
 
Ackbach said:
The term "natural frequency" refers to resonance. So if you have a forced mass-spring system, e.g., and you tune the forcing function to the same frequency as a term in the homogeneous solution, you end up with unstable behavior.

The term "frequency" just refers to what's going on in this thread.

There's also the term "angular frequency", which is represented by $\omega=2\pi f$.

Hope that's as clear as mud.

I am trying to find the natural frequency (eigenfrequency) of $u$.
How would I do that then?
$$
u(x,t) = \sum_{n = 1}^{\infty}\sin\left[\frac{\pi x}{L}\left(n + \frac{1}{2}\right)\right]\left\{A_n\cos\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right] + B_n\sin\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right]\right\}
$$
 
dwsmith said:
I am trying to find the natural frequency (eigenfrequency) of $u$.
How would I do that then?
$$
u(x,t) = \sum_{n = 1}^{\infty}\sin\left[\frac{\pi x}{L}\left(n + \frac{1}{2}\right)\right]\left\{A_n\cos\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right] + B_n\sin\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right]\right\}
$$

Well, I could be wrong, but I would say that all of your
$$f_{n}=\frac{c\left(n + \frac{1}{2}\right)}{2L}$$
are the eigenfrequencies. I don't think there's one single eigenfrequency.