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## Homework Statement

A 25 kg bear slides, from rest, 8 m down a lodgepole pine tree, moving with a speed of 6.4 m/s just before hitting the ground

(a) What change occurs in the gravitational potential energy of the bear-Earth system during the slide?

W = F*D

W = (m*a)*D

W = 1960

(b) What is the kinetic energy of the bear just before hitting the ground?

KE = 0.5*m*v^2

KE = 512

(c) What is the average frictional force that acts on the bear?

E

_{i}= m*g*h = 1960

E

_{f}= 0.5*m*v^2

W = -F

_{k}*h

E

_{i}+ W = E

_{f}

1960 + (-F

_{k}*h) = 512

-F

_{k}= 120.67

Could someone check to see if i solved this correctly?

Thanks!