Friction force needed for merry-go-round circular motion

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Socom
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Homework Statement


A 45-kg merry-go-round worker stands on the ride's platform 6.3m from the center. If her speed as she goes around the circle is 4.1 m/s, what is the force of friction necessary to keep her from falling off the platform?


Homework Equations


f=ma
Ac=v^2/r
mu=v^2/rg (derived from [mu]g=v^2/r


The Attempt at a Solution


I don't believe the 6.3m is relevant to the problem.

I believe Fnet=sigmaFx=theta=m*a

I am not really sure how to attack this problem and some help would be very nice.
 
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Socom said:

Homework Statement


A 45-kg merry-go-round worker stands on the ride's platform 6.3m from the center. If her speed as she goes around the circle is 4.1 m/s, what is the force of friction necessary to keep her from falling off the platform?

Homework Equations


f=ma
Ac=v^2/r
mu=v^2/rg (derived from [mu]g=v^2/r

The Attempt at a Solution


I don't believe the 6.3m is relevant to the problem.

I believe Fnet=sigmaFx=theta=m*a

I am not really sure how to attack this problem and some help would be very nice.

You got the right equation:

[tex]\mu = \frac{v^2}{rg}[/tex]

now tell me... what does the r mean in:

[tex]A_c = \frac{v^2}{r}[/tex]