How Does the Coriolis Effect Influence Acceleration on a Merry-Go-Round?

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Homework Help Overview

The discussion revolves around the Coriolis effect and its influence on the acceleration of a ball on a merry-go-round, particularly from the perspective of an observer on the platform. Participants are exploring the nuances of acceleration in non-inertial reference frames.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are examining the relationship between the perceived trajectory of the ball and its acceleration, questioning the implications of constant velocity versus the presence of acceleration in a rotating frame. There are discussions about the nature of normal and tangential acceleration, as well as the roles of Coriolis and centrifugal forces.

Discussion Status

The conversation is ongoing, with participants expressing confusion and seeking clarification on the definitions and characteristics of acceleration in the context of the problem. Some have acknowledged the contradiction in statements regarding velocity and acceleration, while others are attempting to reconcile these ideas with the forces at play.

Contextual Notes

Participants are navigating the complexities of non-inertial reference frames and the effects of various forces, including Coriolis and centrifugal forces, on the motion of the ball. There is an emphasis on understanding the problem's constraints and the definitions being used.

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Homework Statement
Two boys are sitting diametrically opposite on a merry go round. The platform has a constant angular velocity. Then, the boy ##A## throws a ball to the boy ##B##. This ball has a horizontal velocity relative to the platform and directed to ##B##, and has no horizontal acceleration. What's the acceleration with respect to ##B## along the plane of the platform at the instant after thrown?
Relevant Equations
##\vec a=\vec a_B + \vec{\dot \omega} \times \vec r + \vec \omega \times (\vec \omega \times \vec r) + 2. (\vec \omega \times \vec v_{rel}) + \vec a_{rel}##
This is a tipical Coriolis effect example, and I know what the trajectory drawn by the ball looks like from the perspective of B, and from the perspective of someone outside. But the acceleration with respect to ##B## is 0, isn't it? Because the problem says "the ball has no horizontal acceleration". If not, what would it be? I guess it would be an acceleration pointing outside the platform because that would be the acceleration that moves the ball from the perspective of ##B##
 
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Like Tony Stark said:
Coriolis effect example, and I know what the trajectory drawn by the ball looks like from the perspective of ##B##, and from the perspective of someone outside. But the acceleration with respect to ##B## is 0,

Do you see why the bolded phrases are contradictory? If ##B## perceives a path which is not straight in his frame of reference, then by definition the velocity can not be constant.

 
RPinPA said:
Do you see why the bolded phrases are contradictory? If ##B## perceives a path which is not straight in his frame of reference, then by definition the velocity can not be constant.

I didn't express myself correctly. Yes, it has an acceleration because it doesn't follow a straight line, so it must have an acceleration. But how would that acceleration be? Because the task says "what's the acceleration of the ball with respect to ##B##?#, which are its characteristics? It only has normal acceleration and not tangential because the velocity is constant, and it points outside the merry go round. Would that be ok?
 
Like Tony Stark said:
I didn't express myself correctly. Yes, it has an acceleration because it doesn't follow a straight line, so it must have an acceleration. But how would that acceleration be? Because the task says "what's the acceleration of the ball with respect to ##B##?#, which are its characteristics? It only has normal acceleration and not tangential because the velocity is constant, and it points outside the merry go round. Would that be ok?
I am having difficulty following the logic here.

We have already agreed that the velocity is not constant. So it seems that you mean that the speed is constant because Coriolis is the only force in play. Indeed, Coriolis is always perpendicular to the velocity vector and does not affect speed. But that ignores the centrifugal pseudo-force. Centrifugal force can affect speed.
 

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