Friction with two masses (Help)

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SUMMARY

The discussion focuses on a physics problem involving two masses: a 40 kg slab on a frictionless floor and a 10 kg block on top, with static and kinetic friction coefficients of 0.6 and 0.4, respectively. A horizontal force of 100 N is applied to the block, resulting in an acceleration of 6.1 m/s² for the block. The acceleration of the slab is determined to be 1.5 m/s², calculated by considering the frictional force acting between the block and the slab. Free Body Diagrams are essential for visualizing the forces acting on both masses to solve the problem accurately.

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  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of static and kinetic friction coefficients
  • Ability to draw and interpret Free Body Diagrams
  • Basic concepts of acceleration and force interaction
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DJWise
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1. A slab of mass 40 kg rest on a frictionless floor, and a block of mass 10kg rest on top of the slab. Between block and slab, the coefficient of static friction is 0.6, and the coefficient for kinetic friction is 0.4. The block is pulled by a horizontal force (to the right) of magnitude 100N. In unit vector notation, what are the resulting accelerations of a.) the block and b.) the slab?



2. F=ma



3. Some how got the top mass to be accelerating 6.1 m/s^2 but can't get what the bottom slab is accelerating at
 
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DJWise said:
1. A slab of mass 40 kg rest on a frictionless floor, and a block of mass 10kg rest on top of the slab. Between block and slab, the coefficient of static friction is 0.6, and the coefficient for kinetic friction is 0.4. The block is pulled by a horizontal force (to the right) of magnitude 100N. In unit vector notation, what are the resulting accelerations of a.) the block and b.) the slab?



2. F=ma



3. Some how got the top mass to be accelerating 6.1 m/s^2 but can't get what the bottom slab is accelerating at


I agree with your answer for the acceleration of the top block.

Have you drawn Free Body Diagrams for each mass? If not, do so (separate diagrams for each), making sure to show all forces acting on each one.

If you look at how you got that answer, one component should include a frictional force. Remember that a frictional force will have an equal and opposite force on each of the surfaces on which it acts.

Also remember that the force acting on each mass independently will be equal to the total force acting on the system (100 N to the right).
 

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