Frobenius theorem applied to frame fields

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Discussion Overview

The discussion revolves around the application of Frobenius's theorem to frame fields within the context of differential geometry. Participants explore the conditions for complete integrability of smooth distributions on manifolds, particularly focusing on the implications of the Lie bracket of vector fields in frame fields and its relation to the Straightening theorem.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants suggest that Frobenius's theorem holds true for any smooth frame field, asserting that the Lie bracket of frame field vectors lies within the span of those vectors.
  • Others argue that Frobenius's theorem reduces to the condition that frame field vectors must commute, stating that while commuting implies closure under the Lie bracket, it is not a necessary condition.
  • A participant questions how Frobenius's theorem relates to the Straightening theorem, seeking clarification on the implications of both theorems regarding integrability and local coordinates.
  • Another participant provides an example to illustrate the concept of flow associated with a vector field, discussing how this flow can be represented in a coordinate system.
  • Some participants express confusion about the definition of flow and its relationship to the function defined on the manifold, prompting further clarification.
  • A later reply emphasizes that the Frobenius theorem is always true for frame fields, particularly when considering the tangent bundle of a manifold and the conditions for subbundles.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the implications of Frobenius's theorem for frame fields, with multiple competing views on the necessity of commutation and the relationship to the Straightening theorem remaining unresolved.

Contextual Notes

Participants note the complexity of visualizing the concepts discussed, particularly in higher dimensions, and the dependence on specific definitions of terms like flow and integrability.

  • #31
cianfa72 said:
Sorry, but the above Borel subgroup of ##\operatorname{SL}(2,\mathbb R)## is not itself a Lie group ?
It is of course a Lie group. It's a two-dimensional smooth manifold. A typical element looks like
$$
\begin{pmatrix}e^t&c\\0&e^{-t}\end{pmatrix}
$$
The toral element, the diagonal matrix is a flow through time, and the unipotent element makes it non-abelian. The group is
$$
\biggl\langle \begin{pmatrix}e^t&c\\0&e^{-t}\end{pmatrix} \biggr\rangle =\left\{\left.\begin{pmatrix}x&y\\0&z\end{pmatrix}\,\right|\,x\cdot z= 1\right\} .
$$
 

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