Frobenius theorem applied to frame fields

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SUMMARY

The discussion centers on the application of Frobenius's theorem to smooth frame fields on n-dimensional smooth manifolds. It establishes that for a smooth frame field defined by n linearly independent smooth vector fields, the Lie bracket [X,Y] of any two frame field vectors X and Y lies in the span of those vectors at each point, confirming that the Frobenius condition for complete integrability is satisfied. The conversation also explores the relationship between Frobenius's theorem and the Straightening theorem, emphasizing that while the former provides conditions for integrability of subbundles, the latter relates to defining local coordinates along flows of vector fields.

PREREQUISITES
  • Understanding of Frobenius's theorem in differential geometry
  • Knowledge of smooth manifolds and tangent bundles
  • Familiarity with Lie brackets and Lie algebras
  • Concept of flows in the context of vector fields
NEXT STEPS
  • Study the implications of Frobenius's theorem on the integrability of distributions
  • Explore the Straightening theorem and its applications in differential geometry
  • Learn about the properties of tangent bundles and their relation to vector fields
  • Investigate the concept of flows in differential equations and their geometric interpretations
USEFUL FOR

This discussion is beneficial for mathematicians, particularly those specializing in differential geometry, as well as students and researchers interested in the applications of Frobenius's theorem and its connection to other geometric theorems.

  • #31
cianfa72 said:
Sorry, but the above Borel subgroup of ##\operatorname{SL}(2,\mathbb R)## is not itself a Lie group ?
It is of course a Lie group. It's a two-dimensional smooth manifold. A typical element looks like
$$
\begin{pmatrix}e^t&c\\0&e^{-t}\end{pmatrix}
$$
The toral element, the diagonal matrix is a flow through time, and the unipotent element makes it non-abelian. The group is
$$
\biggl\langle \begin{pmatrix}e^t&c\\0&e^{-t}\end{pmatrix} \biggr\rangle =\left\{\left.\begin{pmatrix}x&y\\0&z\end{pmatrix}\,\right|\,x\cdot z= 1\right\} .
$$
 

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