From the marginal cost to the total cost.

  • Context: MHB 
  • Thread starter Thread starter Francobati
  • Start date Start date
  • Tags Tags
    Marginal
Click For Summary
SUMMARY

This discussion focuses on the integration of marginal cost to derive total cost in a mathematical context. The marginal cost function is defined as $MC_{i}(q)_{i}=q_{i}+10$, leading to the total cost equation $TC=\frac{1}{2}q_i^2+10q_{i}$. The integration process involves applying the Fundamental Theorem of Calculus (FTOC) and assumes no fixed costs ($C_F=0$), resulting in the total cost formula $C_T=\frac{1}{2}q^2+10q$ for two companies, $i=1,2$. The parameters used in the calculations are $(a,b)=(1,10)$.

PREREQUISITES
  • Understanding of marginal cost functions
  • Familiarity with integration techniques in calculus
  • Knowledge of the Fundamental Theorem of Calculus (FTOC)
  • Basic concepts of cost functions in economics
NEXT STEPS
  • Study integration of functions in calculus
  • Learn about cost functions in microeconomics
  • Explore applications of the Fundamental Theorem of Calculus
  • Investigate linear marginal cost functions and their implications
USEFUL FOR

Students and professionals in economics, mathematicians focusing on calculus applications, and anyone interested in cost analysis in business scenarios.

Francobati
Messages
20
Reaction score
0
Hello. Can you help me figure out how to pass, integrating, by the marginal cost: $MC_{i}(q)_{i}=q_{i}+10$ to the total cost: $TC=\frac{1} {2}q_i^2+10q_{i}$?
$i=1,2$, are the two companies. $q_{i}$ is the quantity. What are the calculations?
 
Physics news on Phys.org
Given a marginal cost $C_M$, a fixed cost $C_F$ and a quantity $q$, we are to assume (using the definition of marginal cost) for the total cost $C_T$:

$$\d{C_T}{q}=C_M$$

Now, if we integrate both sides w.r.t $q$, exchange the dummy variables of integration (and use a linear marginal cost function) and using the given boundaries, we obtain:

$$\int_{C_F}^{C_T}\,du=\int_0^q av+b\,dv$$

Applying the FTOC, there results:

$$C_T-C_F=\frac{a}{2}q^2+bq$$

Now, for this problem, it would appear there are no fixed costs ($C_F=0$), and we are given $(a,b)=(1,10)$, hence:

$$C_T=\frac{1}{2}q^2+10q$$
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K