From what height was the pot dropped at?

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In summary, the flowerpot takes 0.2 seconds to fall past a window that is 1.9 meters above the ground. Using the equation d = v1*t + (1/2)at^2, the vertical distance traveled by the pot is 0.196 meters. However, since the pot has already been falling for some time before passing the window, the book's answer of 3.7 meters suggests that there is additional information needed to solve this problem.
  • #1
Fentow
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Homework Statement


A falling flowerpot takes 0.2s to fall past a window which is 1.9m above ground. From what height was the pot dropped at?


Homework Equations


d = v1*t + (1/2)at^2


The Attempt at a Solution


I'm not sure what to do with the 1.9m above ground...

D = 0*0.2 + (1/2)(9.8m/s^2)(0.2)^2
D = 0.196

The book answer is 3.7m though, which is way off. I'm sure I have to use 1.9m to find the answer, but I'm at a loss right now. Help! Please and thank you!
 
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  • #2
The flower pot has already been falling for some time before it passes the top of the window.

There are three things you know about this situation: acceleration, time to pass window, and vertical distance of window. What can this information tell you about how fast it was moving at the top of the window?
 
  • #3


Based on the given information, we can use the equation d = v1*t + (1/2)at^2 to find the initial height of the pot. The first step is to determine the initial velocity, v1. Since the pot is initially at rest, v1 = 0. Next, we can plug in the values for time (t = 0.2s) and acceleration (a = 9.8m/s^2) and solve for d.

d = (0)(0.2) + (1/2)(9.8m/s^2)(0.2)^2
d = 0 + 0.196
d = 0.196m

However, this only gives us the distance the pot has fallen in 0.2s. To find the initial height, we need to subtract this distance from the total distance the pot has fallen, which is 1.9m.

Initial height = 1.9m - 0.196m = 1.704m

Therefore, the pot was dropped from a height of 1.704m. It is important to note that this calculation assumes that the pot was dropped from rest and there was no air resistance. If these assumptions are not true, the calculated initial height may differ from the actual height.
 

Related to From what height was the pot dropped at?

1. What is the importance of knowing the height at which the pot was dropped?

The height at which the pot was dropped is important because it can affect the impact force and potential damage caused by the falling object. It also plays a role in determining the kinetic energy and velocity of the pot at impact.

2. How can the height at which the pot was dropped be measured?

The height at which the pot was dropped can be measured using various methods such as a measuring tape, a ruler, or a measuring stick. It can also be calculated using equations related to gravity and time.

3. Does the shape or weight of the pot affect the height from which it should be dropped?

Yes, the shape and weight of the pot can affect the height from which it should be dropped. Heavier or bulkier pots may require a lower drop height to achieve the desired impact force, while lighter or more aerodynamic pots may require a higher drop height.

4. Are there any safety precautions to consider when dropping a pot from a certain height?

Yes, it is important to take safety precautions when dropping a pot from a height. This can include wearing protective gear, ensuring the area is clear of people or objects, and using a secure platform or ladder to reach the desired drop height.

5. How does the height from which the pot is dropped affect its breaking point?

The height from which the pot is dropped can affect its breaking point as it can determine the amount of force and energy the pot will experience upon impact. Dropping a pot from a higher height can result in a higher impact force and potentially cause the pot to break or shatter.

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