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From what height was the pot dropped at?

  1. Oct 15, 2007 #1
    1. The problem statement, all variables and given/known data
    A falling flowerpot takes 0.2s to fall past a window which is 1.9m above ground. From what height was the pot dropped at?

    2. Relevant equations
    d = v1*t + (1/2)at^2

    3. The attempt at a solution
    I'm not sure what to do with the 1.9m above ground...

    D = 0*0.2 + (1/2)(9.8m/s^2)(0.2)^2
    D = 0.196

    The book answer is 3.7m though, which is way off. I'm sure I have to use 1.9m to find the answer, but I'm at a loss right now. Help! Please and thank you!
  2. jcsd
  3. Oct 16, 2007 #2

    Chi Meson

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    Science Advisor
    Homework Helper

    The flower pot has already been falling for some time before it passes the top of the window.

    There are three things you know about this situation: acceleration, time to pass window, and vertical distance of window. What can this information tell you about how fast it was moving at the top of the window?
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