1. The problem statement, all variables and given/known data A cat spots a flowerpot that sails first up and then down past an open window. The post is in view for a total of 0.50 seconds, and the top-to-bottom height of the window is 2.00 m. How high above the window top does the flower pot go? Answer: 2.34 2. Relevant equations y = (1/2)g*t^2 + Vo*t + yo 3. The attempt at a solution Let's see this is what I did. I tried to combine the known height of the window with the unknown height of the pot and used one of the above to do so. hp = height of the pot hw = height of the window y = (1/2)g*t^2 + Vo*t + yo hw + hp = (1/2)g*t^2 + Vo*t 2 + hp = (1/2)g*t^2 + 0*t 2 + hp = (1/2)(9.8)(0.50^2) hp = (4.9)(0.25) It's obvious that is wrong. I think I need to find it's initial velocity since it was already moving, but I'm not sure.