Function's Fun f(x^2−2016x)=f(x)⋅x+2016

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The discussion centers on solving the functional equation f(x^2 - 2016x) = f(x)·x + 2016 to determine the value of f(2017). Participants clarify that the expression x^2 - 2016x can be set to 2017, leading to the equation x^2 - 2016x - 2017 = 0. This results in two potential solutions for x: -1 and 2017. Ultimately, the conclusion is that f(2017) = -1, derived from the equation -2016 = 2016f(2017).

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f(x^2*2016x) = f(x)x+2016
Then f(2017) = ?
 
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Isn't "x^2*2016x" the same as "2016x^3"?
 
Thanks, skeeter. That sounds more reasonable.

f(x^2- 2016x)= f(2017) if x^2- 2016x= 2017. That is the same as x^2- 2016x- 2017= (x+ 1)(x- 2017)= 0 so either x= -1 or x= 2017.

So either f(2017)= -1(f(-1))+ 2016 or f(2017)= 2017 f(2017)+ 2016.

For the latter, -2016= 2016 f(2017) so f(2017)= -1.
 

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