Fundamental frequency of a guitar string?

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SUMMARY

The fundamental frequency of a guitar string tuned to B3 (245 Hz) can be calculated using the equation f_n = n(v/2L). For a 63.5-cm string, the wave speed is determined to be 311 m/s. When the tension is increased by 1.0%, the new tension T_2 becomes 1.01T_1, leading to a new wave speed calculated as v = 311 * √1.01. This results in a new fundamental frequency of 246 Hz, demonstrating a clear understanding of the relationship between tension and frequency.

PREREQUISITES
  • Understanding of wave mechanics and transverse waves
  • Familiarity with the fundamental frequency equation f_n = n(v/2L)
  • Knowledge of tension and its effect on wave speed
  • Basic algebra for manipulating equations
NEXT STEPS
  • Explore the relationship between tension and frequency in string instruments
  • Learn about wave speed calculations in different mediums
  • Investigate the effects of string length on fundamental frequency
  • Study the principles of harmonic frequencies in musical acoustics
USEFUL FOR

Musicians, physics students, and anyone interested in the acoustics of string instruments will benefit from this discussion.

erik-the-red
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Question:

One of the 63.5-cm-long strings of an ordinary guitar is tuned to produce the note {\rm B_3} (frequency 245 Hz) when vibrating in its fundamental mode.

1.

If the tension in this string is increased by 1.0%, what will be the new fundamental frequency of the string?

The first part of the question asked for the speed of transverse waves on the string.

I used the equation f_n = n\frac{v}{2L}. The fundamental frequency is given, so f_1 = 245 = \frac{v}{2*.635}, so v = 311 m/s.

This is correct.

In approaching the second part, I'm thinking T_2 = 1.01T_1. Since v = \sqrt{\frac{T}{\mu}}, should I assume that the new speed will be 311 * \sqrt{1.01}?

Thus giving a new fundamental frequency of 246 Hz?
 
Last edited:
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Not only is this correct, it shows good insight into proportionalities. Keep it up!
 

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