Fundamental thermo systems problem

[kik369]

1. Unit mass of a fluid at a pressure of 3 bar, and with a specific volume of 0.18 m³/kg, contained in a cylinder behind a piston expands reversibly to a pressure of 0.6 bar according to the law p = c/v², where c is a constant. Calculate the work done during the process.
2. P₁V₁=P₂V₂
3. I know that the answer is 29.82 J/kg out of the system, but how to get it?

 

[RTW69]

c=p₁*v1² but work=∫p*dv=∫c/v²*dv=c∫dv/v² the rest is basic calculus. The answer units should be kj/kg

 

[RTW69]

c=Subscript[p, 1]*Subsuperscript[v, 1, 2] but work = \[Integral]p \[DifferentialD]v =\[Integral]c/v^2 \[DifferentialD]v = c \[Integral]1/v^2 \[DifferentialD]v the rest is basic calc. I believe the answer units is KJ/Kg

 

[RTW69]

Guess I can't copy mathematica text into the message box

 

[kik369]

Thank you! I'll go through this tomorrow. I've been working on these problems the whole day. It is time for me to take a break. I appreciate the reply.