Fundemental Lemma of the Calculus of Variations

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SUMMARY

The Fundamental Lemma of the Calculus of Variations states that if a continuous function f: [a,b] -> R satisfies the integral condition ab f(t)h(t)dt = 0 for all h ∈ C0,01([a,b], R), then f(x) = 0 for all x in [a,b]. The discussion clarifies that this lemma does not extend to higher dimensions, such as Rk, as additional conditions regarding integrals over surfaces and three-dimensional regions are necessary. The conclusion of the lemma was initially omitted by the user but is critical for understanding its implications.

PREREQUISITES
  • Understanding of the Fundamental Lemma of the Calculus of Variations
  • Knowledge of continuous functions and their properties
  • Familiarity with the space of C0,01([a,b], R)
  • Basic concepts of integration in single-variable calculus
NEXT STEPS
  • Study the implications of the Fundamental Lemma in higher dimensions
  • Explore the concept of integrals over surfaces and regions in Rk
  • Learn about the applications of the Calculus of Variations in physics and engineering
  • Investigate related theorems in functional analysis and their proofs
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Mathematicians, physics students, and researchers in optimization and variational calculus who seek a deeper understanding of the Fundamental Lemma and its applications in various dimensions.

Niles
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Hi all.

In my notes I wrote down from the blackboard, I wrote

[Fundemental Lemma of the Calculus of Variations] Let f : [a,b] -> R be continuous and suppose that

<br /> \int_a^b f(t)h(t)dt = 0<br />

for all h\in C_{0,0}^1([a,b], R), where C_{0,0}^1([a,b], R) is the space of C1 parametrized curves O : [a,b] -> R that start and end in 0.

I suspect that I missed some k's when writing this down from the blackboard. Am I correct when I say that this also works if we are in Rk?
 
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What you are missing is the conclusion of the lemma. You have only stated the hypotheses. IF f is a function having those properties then- f(x)= 0 of all x in [a,b].

No, you are not correct that this also works in Rk. In higher dimensions just integrating on paths is not enough. You would also have to know that integral was 0 on all surfaces, all three dimensional regions, etc. up to the dimension of the space.
 
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Thank you. Yes, for some reason I didn't type in the conclusion, even though I did write it down in class. Thanks.
 

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