Galvanic Cell Reactions and Potential Calculation

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Discussion Overview

The discussion revolves around the reactions and potential calculations of a galvanic cell involving aluminum (Al) and iron (Fe). Participants are analyzing the anode and cathode reactions, overall cell potential, and the direction of ion and electron flow based on a provided diagram.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant identifies Fe as the cathode and Al as the anode, proposing the overall cell reaction as 2Al + 3Fe^2+ => 2Al^3+ + 3Fe.
  • Another participant questions the inclusion of "6e-" in the overall reaction and suggests a breakdown of the half-reactions for clarity.
  • There is a mention of the flow of electrons and ions in the galvanic cell, with a participant noting the omission of directional details in the initial response.
  • Some participants express uncertainty about the flow of electrons, with one suggesting they might be going "uphill," indicating a potential misunderstanding of the electron flow direction.

Areas of Agreement / Disagreement

Participants generally agree on the identification of the anode and cathode, but there is disagreement regarding the details of the reactions and the flow of electrons and ions. The discussion remains unresolved on these points.

Contextual Notes

Participants have not seen the diagram referenced, which may limit their ability to fully engage with the problem. There are also unresolved questions about the correct interpretation of the reactions and the flow of charge carriers.

johnk
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Hey guys! I'm not sure if I solved this correctly. If you could please take a look at my answers I'd really appreciate it. Thank you in advance!

(I tried using the super subscript option but I started to confuse myself because of all the coding so I just stuck with the up arrow (^) I hope you guys don't mind too much) Thanks again

Homework Statement


The following figure shows a diagram of an Al/Fe galvanic cell. Use the diagram to
answer the questions that follow it.

25zo5ls.png


a) Predict the anode, cathode, and overall cell reactions that occur as this cell operates.
b) Predict the overall cell potential.
c) Describe the direction of ion and electron flow in the diagram.

The Attempt at a Solution



a)
• Fe = Cathode
• Al = Anode
• Al(s) => Al^3+(aq) + 3e^- Fe^2+(aq) + 2e^- => Fe(s)
2(Al => Al^3+ + 3e^-
3(Fe^2+ + 2e^- => Fe)
=2Al + 3Fe^2+ + 6e^- => 2Al^3+ + 6e^- + 3Fe
=2Al + 3Fe^2+ => 2Al^3+ + 3Fe

b)
Al(s) => Al^3+(aq) + 3e^- E=1.66
Fe^2+(aq) + 2e^- => Fe(s) E=-0.41
Overall E= 1.25

c) In an operating galvanic cell, electrons flow through the conducting wire, while ions flow through the solution and salt bridge.
 
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I couldn't see the picture, but I guess this is right

johnk said:
a)
=2Al + 3Fe^2+ + 6e^- => 2Al^3+ + 6e^- + 3Fe
What is the 6e- for?
The reaction goes like this: 2Al => 2Al3+ + 6e-
then 3Fe2+ + 6e- => 3Fe

johnk said:
c) In an operating galvanic cell, electrons flow through the conducting wire, while ions flow through the solution and salt bridge.
Umm... you forgot to mention the direction of the flow of the electrons and ions. :biggrin:
The electrons flow from the cathode(+) to the anode(-). The positive salt ions go to the anode(-) and the negative to the cathode(+)
 
z.js said:
The electrons flow from the cathode(+) to the anode(-).

You sure? Seems they'd be going "uphill" so to speak.
 
Really? Don't the electrons come from the anode? (I mean... oops sorry:redface:)
 
z.js said:
I couldn't see the picture, but I guess this is right


What is the 6e- for?
The reaction goes like this: 2Al => 2Al3+ + 6e-
then 3Fe2+ + 6e- => 3Fe


Umm... you forgot to mention the direction of the flow of the electrons and ions. :biggrin:
The electrons flow from the anode(-) to the cathode(+). The positive salt ions go to the anode(-) and the negative to the cathode(+)

Yep that's right! thanks a lot!:biggrin:
 

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