Gambler's Ruin in Matlab: Solving the Loop Problem

[JohnPrior3]

For Matlab, I need to write a program where a Gambler starts with 5 dollars and runs out with 1 dollar bets. The house has favorable odds of 70/30. I have gotten very far, but I can't find out how to end the loop when the gambler reaches 0. Here is my script:

A = 5

n=100;

x=rand(1,n);

    for i=1:n-1

        if x(i)>0.3

          A=A-1

        else

          A=A+1

        end
end

My script runs the 100 times and leaves me with a negative number. Everything works for the script, except ending at 0. I tried doing a while loop but it didn't work.

 

[mfb]

The while loop is a better approach. Can you show that?

You can use [code] tags to make it easier to show code:

for i=1:n-1
  if x(i)>0.3
    A=A-1

 

[donpacino]

For Matlab, I need to write a program where a Gambler starts with 5 dollars and runs out with 1 dollar bets. The house has favorable odds of 70/30. I have gotten very far, but I can't find out how to end the loop when the gambler reaches 0. Here is my script:

A = 5

n=100;

x=rand(1,n);

    for i=1:n-1

        if x(i)>0.3

          A=A-1

        else

          A=A+1

        end
end

My script runs the 100 times and leaves me with a negative number. Everything works for the script, except ending at 0. I tried doing a while loop but it didn't work.

So what you're saying is IF the gambler has no money, then he can't gamble??