Gas molecule and moving wall collision

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SUMMARY

The discussion centers on the collision of a gas molecule with a moving wall acting as a frictionless piston. The gas molecule, with mass m, approaches the wall at velocity v = (vx, 0, 0). The key conclusion is that in the wall's rest frame, the molecule's velocity transforms to v = u - vx, and upon rebounding elastically, the new velocity is the negative of this value. The correct transformation back to the lab frame is essential for accurate results, particularly since the molecule's initial speed exceeds that of the wall.

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Homework Statement



Gas is contained in an enclosure in which one of the walls is a plane of area A. The wall
acts as a frictionless piston, moving with constant velocity u in the positive x-direction,
thus increasing the volume V of gas enclosed.

A gas molecule of mass m approaches the moving wall at velocity v = (vx, 0, 0),
relative to the enclosure. Obtain an expression for the velocity of the molecule after
it rebounds elastically from the moving wall.

Homework Equations





The Attempt at a Solution



So in the rest frame of the wall you have v = u - vx, and the rebounded velocity is just the negative of this. But how do you transform back to the lab frame? Or was it unnecessary transforming into the rest frame of the wall in the first place? I am confused?
 
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Remember, the molecule is traveling faster than the wall, so you might want it set as v = vx -u. Also, once you solve it you will definitely need to go back to the lab frame.
 

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