Gauge eigenstates vs. Mass eigenstates

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SUMMARY

The discussion centers on the transformation of gauge eigenstates to mass eigenstates within the context of the Standard Model of particle physics. Participants clarify that gauge eigenstates, often referred to as gauge quarks, are unphysical and defined through their interactions with other fields in the Lagrangian. The transformation to mass eigenstates involves diagonalizing the mass matrices generated by Yukawa coupling, which determines the masses and flavor mixing of quarks. Additionally, the eigenvalue equations related to gauge groups, such as SU(2), are discussed, emphasizing the relationship between gauge bosons and fermions as eigenvectors of the corresponding generators.

PREREQUISITES
  • Understanding of the Standard Model of particle physics
  • Familiarity with gauge theory and gauge groups, specifically SU(2)
  • Knowledge of Yukawa coupling and its role in mass generation
  • Basic concepts of eigenvalue equations and their application in quantum mechanics
NEXT STEPS
  • Study the process of diagonalization of mass matrices in particle physics
  • Explore the role of Yukawa coupling in the Standard Model
  • Learn about the properties of gauge groups, focusing on SU(2) and its representations
  • Investigate the implications of flavor mixing in neutrino oscillations
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Physicists, graduate students in theoretical physics, and anyone interested in the mathematical foundations of particle interactions and the Standard Model.

Kontilera
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Hello fellow physicsforumists.
I am currently looking at the standard model and one of the key ingridients is to rotate the gauge eigenstates to the mass eigenstates by a transformation acting on their family index. The problem is that I can't really see what we are doing.

The mass eigenstates are such that the massterm coefficients matrices are diagonal. But how do we define gauge eigenstates to begin with?

Please, if you have the energy to write some word about this I would be thankful.

Best Regards
Kontilera
 
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gauge eigenstates are unphysical.Each quark in standard model has right handed components because they are massive.Lagrangian is first written in terms of the doublet and singlet fields which contain these unphysical quarks which are termed as gauge quarks or sometimes gauge eigenstates.When you use yukawa coupling to give masses to quarks,a mass matrix is generated.these determine the masses and flavour mixing of quarks.The quark fields used before(SSB) are unphysical gauge eigenstes,you have to find the physical or mass eigenstates by transforming the quark mass matrices into diagonal form.
 
The unphysical gauge eigenstates are defined based on the other fields that will be connected to it through the gauge interaction, so for instance there is a term like uwd' in the Lagrangian which represents the interaction of a u quark with a W boson and a d' unphysical quark. The d' along with the s' and d' can be related to the physical (mass eigenstates) fields d, s, and b through a "rotation".
 
Thanks for the answers. I helped me some but I'm not sure I understand why they are referred to as gauge eigenstates.. is there an eigenvalue equation?
 
Kontilera said:
Thanks for the answers. I helped me some but I'm not sure I understand why they are referred to as gauge eigenstates.. is there an eigenvalue equation?
They are more commonly referred as gauge quarks,gauge eigenstate is just misnomer.They are written like like that because they relate to physical mass eigenstates.
 
Kontilera said:
Thanks for the answers. I helped me some but I'm not sure I understand why they are referred to as gauge eigenstates.. is there an eigenvalue equation?

andrien said:
They are more commonly referred as gauge quarks,gauge eigenstate is just misnomer.They are written like like that because they relate to physical mass eigenstates.

I'm a little rusty on my group theory, but I don't think it's a misnomer. The relevant eigenvalue equations are the ones where the operator is a Cartan generator of one of the gauge groups right? Or some such thing. For instance if we consider SU(2), then before symmetry breaking the 3 (massless) gauge bosons are eigenvectors of the diagonal SU(2) generator, in the 3x3 (I think this is the adjoint?) representation. Similarly the left handed (massless) fermions are eigenvectors of the same generator but in the 2x2 (fundamental?) representation.
 
Err actually maybe it is only the fermions that work like that; I am pretty sure they at least are all eigenvectors of some gauge-group related operator or another.
 

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