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Gauge symmetry and symmetry breaking

  1. Apr 15, 2007 #1
    How would one know in general, whether an original gauge symmetry in the theory is still gauge symmetrical after symmetry breaking? I mean is there a theorem or something like that?
    And the other way around, is there a general way of knowing whether there is the possibility of a hidden, i.e. not manifest gauge symmetry from a theory?
     
    Last edited: Apr 15, 2007
  2. jcsd
  3. Apr 17, 2007 #2

    Haelfix

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    Yes the gauge symmetry is still there in the full theory, its just not manifest anymore b/c the perturbative solution has broken the original symmetry down to a subgroup.

    From the point of view of effective field theory with some set cutoffs, its no longer relevant.

    The only way a gauge symmetry can dissappear in quantum field theory, is if there is an anomaly present. Those sorts of theories are generally believed to be inconsistent.
     
  4. Apr 17, 2007 #3
    That's what I was thinking. I was doing scalar electrodynamics after symmetry breaking, adding the ghost term and the [tex]R_{\xi}[/tex] gauge, computing the one-loop correction to the effective potential.

    The question asked to show that to one-loop correction, the effective potential does not depend on [tex]\xi[/tex]. But my corrections failed to cancel half of the terms with [tex]\xi[/tex].
    That's how this question I posted came into my mind. Perhaps the question was wrong, and indeed the gauge symmetry is no longer manifest after symmetry breaking. Hence, it does depend on [tex]\xi[/tex].
     
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