Gauss's Law Homework: Find Surface Charge Density

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SUMMARY

The discussion focuses on calculating the surface charge density on the ground due to a vertical electric field of 116 N/C. The solution involves applying Gauss's Law, leading to the equation 116 N/C = σ / (ε₀), where σ represents the surface charge density and ε₀ is the permittivity of free space (approximately 8.83 x 10^-12 C²/(N·m²)). The calculated surface charge density is approximately 1.0266 x 10^-9 C/m², indicating a minimal charge density required to maintain the specified electric field conditions.

PREREQUISITES
  • Understanding of Gauss's Law
  • Familiarity with electric fields and surface charge density
  • Knowledge of the permittivity of free space (ε₀)
  • Basic algebra for solving equations
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  • Study the application of Gauss's Law in different geometries
  • Explore the concept of electric fields in conductors
  • Learn about the relationship between electric field strength and surface charge density
  • Investigate the effects of external electric fields on charged surfaces
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Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields and charge distributions in conductive materials.

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Homework Statement


On a clear, sunny day, a vertical electrical field of about 116 N/C points down over flat ground. What is the surface charge density on the ground for these conditions?


Homework Equations





The Attempt at a Solution


116*8.83e-12= 1.0266e-9
 
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That's not much of an explanation of what you did. The interior of the ground is approximately a conductor. You want the effect of the surface charge layer to produce 116V/m above the ground and 0V/m below it when added to the external field.
 

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