GCSE Additional physics - NEED HELP =D

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    Gcse Physics
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Homework Help Overview

The discussion revolves around a physics problem involving a beam of electrons and the current it carries, specifically focusing on calculating the charge in coulombs that passes through a point in the beam per second and the number of electrons corresponding to that charge.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of an ampere and its relationship to coulombs, questioning how to apply these definitions to the problem at hand. There are attempts to clarify the meaning of milli and its impact on calculations.

Discussion Status

The discussion is ongoing, with participants providing hints and guidance regarding the definitions of current and charge. Some express confusion about the calculations, while others encourage revisiting fundamental concepts. There is no explicit consensus on the approach to the problem, and multiple interpretations are being explored.

Contextual Notes

Some participants mention a lack of reference material in their revision guides, which may be contributing to the confusion. The urgency of an upcoming exam is also noted, influencing the tone of the discussion.

olliebellamy
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Homework Statement



A beam of electrons leaves an electrom gun. The current carried by the beam is 4mA. a) How many coulombs of charge pass through a certain point in the beam per second. b) How many electrons pass this point per second?

Homework Equations



KE(j) = Charge of electrons (e) X Accelerating voltage (V)

The Attempt at a Solution



I need to find coulombs, and when only given '4mA' i do not see how i can work this out. I have my exam tomorrow afternoon and need to try to get this cleared up, please help =S
 
Last edited:
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Hey olliebellamy, welcome to PF.

First off, I think you are over complicating things.
Read the question more carefully.
 
How is the ampere defined?
 
Blooming forums went down, sorry for not replying.

ok, I've re-looked at the question. i have no idea how to work out the answer. where do i start =P
 
The forum is undergoing a software upgrade so its the same for everyone at the minute.

Like I mentioned before, what is the definition of an ampere, or equally as good the definition of a coulomb? If you find that out it will help you with the question in hand.
 
in the revision guide i am using, there isn't any reference to the ampere with the Elecrtron Beam section. Just this question with no other information, except that :

the charge on an electron is -1.6x10^-19C

the book i am using is appauling -.-
 
OK well 1 coulomb of charge is the amount of charge that passes a point in a second when a current of 1 ampere is present. So if a current of 4mA is present, how much charge passes a point in a second?
 
4000? or 0.004?
 
Check what milli means again.
 
  • #10
milli is 1/1000 - still I'm confused =[
 
  • #11
If the current is smaller (4mA < 1A), what does that say about what the charge passing? Would it be larger or smaller?
 
  • #12
Sorry, I posted before you edited. The latter is correct, and remember your units if this is for an exam.
 
  • #13
OK - 4mA would be smaller than 1A. In that case i guess the charge would be greater
 
  • #14
can i not just have an answer to thie question from somebody? possibly with an explanation of how they came around with this answer?
 
  • #15
50/50 chance there, Try again :P. If you have a smaller current flowing, less electrons (therefore: charge) would be flowing. Making sense... somewhat?
 
  • #16
no sense what so ever...i'm going to skip this section right now and move onto Work, power and energy...at least i can follow some simple formulae for this subject

i'll just hope that i don't have to work out a coulomb in the exam...cos i really can't do it
 
  • #17
olliebellamy said:
can i not just have an answer to thie question from somebody? possibly with an explanation of how they came around with this answer?

We don't give out answers on this forum as you'll have read when you agreed to the rules when signing up. You had the answer before. 0.004 Coulombs.

The formula you were using effectively was [itex]Q = I t[/itex].
 
  • #18
thanks so much, if that formula could have just been displayed for my knowledge in my revision guide, i would have had nothing to worry about.

now i know the formula, i shalln't forget it,
 

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