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## Homework Statement

Calculate the mass of nitrogen dissolved at room temperature in an 80.0L home aquarium. Assume a total pressure of 1.0 atm and a mole fraction for nitrogen of .78.

## Homework Equations

Mole fraction= moles solute/moles solution

S

_{gas}=K

_{H}x P

_{gas}

K

_{H}= 6.1 x 10

^{-4}M/atm

## The Attempt at a Solution

S

_{gas}= (6.1 x 10

^{-4})(1 atm)

S

_{gas}= 6.1 x 10

^{-4}

6.1 x 10

^{-4}/ 1 L x 80.0 L = 4.88 x 10

^{-2}moles

(4.88 x 10

^{-2}moles) x 28.02 g N

_{s}/ 1 mol = 1.37 g N

_{2}

the correct answer is 1.1 g N

_{2}

Where did I go wrong and where does the mole fraction bit come into play? Thanks!