(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Calculate the mass of nitrogen dissolved at room temperature in an 80.0L home aquarium. Assume a total pressure of 1.0 atm and a mole fraction for nitrogen of .78.

2. Relevant equations

Mole fraction= moles solute/moles solution

S_{gas}=K_{H}x P_{gas}

K_{H}= 6.1 x 10^{-4}M/atm

3. The attempt at a solution

S_{gas}= (6.1 x 10^{-4})(1 atm)

S_{gas}= 6.1 x 10^{-4}

6.1 x 10^{-4}/ 1 L x 80.0 L = 4.88 x 10^{-2}moles

(4.88 x 10^{-2}moles) x 28.02 g N_{s}/ 1 mol = 1.37 g N_{2}

the correct answer is 1.1 g N_{2}

Where did I go wrong and where does the mole fraction bit come into play? Thanks!

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Gen Chem, Factors Affecting Solubility

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