Chemistry - Henry's Law/Raoult's Law

  • Thread starter deviljay
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deviljay
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Homework Statement


At surface of the earth, 0.000488 moles of N2 dissolved in each liter of blood. (Ptot=1 atm at surface, and PN2 = 0.78 atm). Calculate Henry's law constant for N2(g) dissolving into blood at the Earth surface and then calculate the number of moles of N2(g) that would dissolve if PN2 increased from 0.78 to 2.3 atm, corresponding to ~20 meters depth underwater.


Homework Equations


None


The Attempt at a Solution


For the first part of the question, I did the following
Henry's Law states
Solubility = KH * P
therefore
4.88E-4 = KH * 0.78
KH= 6.26E-4 mol/L-atm

However I am unable to calculate the second part of the question, what I have so far
S2.3/S0.78 = 2.3/0.78 = 2.94
S2.3 = 4.88E-4 * 2.94 = 1.43E3 mol/L
Now I know the solubility of N2 at 2.3 atm, how do I approach the problem from here?

Sincerely.

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
Borek
Mentor
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3,716
S2.3/S0.78 = 2.3/0.78 = 2.94
S2.3 = 4.88E-4 * 2.94 = 1.43E3 mol/L

I guess it is just a typo.

Don't round down intermediate values during multistep calculations. That is present them rounded, but for calculations use full precision that is available to you at the moment.

Now I know the solubility of N2 at 2.3 atm, how do I approach the problem from here?

Calculate change for 1L of blood.

I had $2 in my pocket, now I have $5. What was the change?
 

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