Chemistry - Henry's Law/Raoult's Law

[deviljay]

Homework Statement

At surface of the earth, 0.000488 moles of N₂ dissolved in each liter of blood. (P_tot=1 atm at surface, and P_N2 = 0.78 atm). Calculate Henry's law constant for N_2(g) dissolving into blood at the Earth surface and then calculate the number of moles of N_2(g) that would dissolve if P_N2 increased from 0.78 to 2.3 atm, corresponding to ~20 meters depth underwater.

Homework Equations

None

The Attempt at a Solution

For the first part of the question, I did the following
Henry's Law states
Solubility = K_H * P
therefore
4.88E-4 = K_H * 0.78
K_H= 6.26E-4 mol/L-atm

However I am unable to calculate the second part of the question, what I have so far
S_2.3/S_0.78 = 2.3/0.78 = 2.94
S_2.3 = 4.88E-4 * 2.94 = 1.43E3 mol/L
Now I know the solubility of N₂ at 2.3 atm, how do I approach the problem from here?

Sincerely.

 

[Borek]

S_2.3/S_0.78 = 2.3/0.78 = 2.94
S_2.3 = 4.88E-4 * 2.94 = 1.43E3 mol/L

I guess it is just a typo.

Don't round down intermediate values during multistep calculations. That is present them rounded, but for calculations use full precision that is available to you at the moment.

Now I know the solubility of N₂ at 2.3 atm, how do I approach the problem from here?

Calculate change for 1L of blood.

I had $2 in my pocket, now I have $5. What was the change?