General Formula for Solving Differential Equations with y in terms of x

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SUMMARY

The discussion centers on solving the differential equation dy/dx = 2x²y(x² - 1) - 1 and finding a general formula for y in terms of x. The proposed solution, y = Ae^(-2x(x² - 1)), is incorrect due to a misstep in integration. Specifically, the correct integration involves 2/(x² - 1) rather than 2x/(x² - 1), which leads to an error in the solution. The correct partial fraction decomposition is 1/(x² - 1) = 1/(x + 1) - 1/(x - 1).

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Al3ks
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Basically the problem is to take dy/dx = 2x2y(x2 -1)-1 and obtain a general formula for the curve with y in terms of x

My result is y = Ae-2x(x2 -1)
with A being the integration constant.
Im just not sure about it, any help would be very much appreciated
Thanks :)
 
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Hi Al3ks! :smile:

No, that doesn't look right :redface:

I think somewhere in the middle you integrated 2x/(x2 -1) instead of 2/(x2 -1)
 
Either that or you have lost a sign in integrating -1/(x+1)

1/(x^2-1)= 1/(x+1)- 1/(x- 1)
 

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