General Formula for Solving Differential Equations with y in terms of x

[Al3ks]

Basically the problem is to take dy/dx = 2x²y(x² -1)^-1 and obtain a general formula for the curve with y in terms of x

My result is y = Ae^-2x(x² -1)
with A being the integration constant.
Im just not sure about it, any help would be very much appreciated
Thanks :)

 

[tiny-tim]

Hi Al3ks!

No, that doesn't look right …

I think somewhere in the middle you integrated 2x/(x² -1) instead of 2/(x² -1)

 

[HallsofIvy]

Either that or you have lost a sign in integrating -1/(x+1)

1/(x^2-1)= 1/(x+1)- 1/(x- 1)