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## Main Question or Discussion Point

dy/dt + y = Sigma Sin(nt)/n^2

- Thread starter Yr11Kid
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dy/dt + y = Sigma Sin(nt)/n^2

- #2

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Multiply by exp(-(integral)Sigma Sin(nt)/n^2 dx) ) and integrate.

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HallsofIvy

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Is Sigma simply a constant of do you mean an infinite sum?

[tex]\frac{dy}{dt}+ y= \sum_{n=1}^\infty \frac{sin(nt)}{n^2}[/tex]

In any case henlus' suggestion works- although he meant "integrating factor of the form exp(t)", not exp(1).

[tex]\frac{dy}{dt}+ y= \sum_{n=1}^\infty \frac{sin(nt)}{n^2}[/tex]

In any case henlus' suggestion works- although he meant "integrating factor of the form exp(t)", not exp(1).

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You're right.Is Sigma simply a constant of do you mean an infinite sum?

[tex]\frac{dy}{dt}+ y= \sum_{n=1}^\infty \frac{sin(nt)}{n^2}[/tex]

In any case henlus' suggestion works- although he meant "integrating factor of the fore exp(t)", not exp(1).

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