- #1

- 8

- 0

dy/dt + y = Sigma Sin(nt)/n^2

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter Yr11Kid
- Start date

- #1

- 8

- 0

dy/dt + y = Sigma Sin(nt)/n^2

- #2

- 336

- 0

Multiply by exp(-(integral)Sigma Sin(nt)/n^2 dx) ) and integrate.

- #3

- 18

- 0

- #4

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 964

Is Sigma simply a constant of do you mean an infinite sum?

[tex]\frac{dy}{dt}+ y= \sum_{n=1}^\infty \frac{sin(nt)}{n^2}[/tex]

In any case henlus' suggestion works- although he meant "integrating factor of the form exp(t)", not exp(1).

[tex]\frac{dy}{dt}+ y= \sum_{n=1}^\infty \frac{sin(nt)}{n^2}[/tex]

In any case henlus' suggestion works- although he meant "integrating factor of the form exp(t)", not exp(1).

Last edited by a moderator:

- #5

- 18

- 0

Is Sigma simply a constant of do you mean an infinite sum?

[tex]\frac{dy}{dt}+ y= \sum_{n=1}^\infty \frac{sin(nt)}{n^2}[/tex]

In any case henlus' suggestion works- although he meant "integrating factor of the fore exp(t)", not exp(1).

You're right.

Share:

- Replies
- 2

- Views
- 3K

- Replies
- 3

- Views
- 4K