General Solution of the first order differential equation

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SUMMARY

The discussion focuses on solving the first-order differential equation represented as dy/dt + y = ∞Σn=1 Sin(nt)/n². This equation is structured as dy/dt = P(t)y(t) + Q(t), where P(t) is defined as -1 and Q(t) is the summation of sin(nt)/n² for n starting from 1. The solution utilizes the formula y(t) = exp(∫P(t) dt) * (∫Q(s) exp(-∫P(s) ds) ds) evaluated at s=t, providing a clear method for finding the general solution.

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  • Understanding of first-order differential equations
  • Familiarity with integration techniques
  • Knowledge of series summation, particularly Fourier series
  • Proficiency in mathematical notation and functions
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dy/dt + y =\infty\sumn=1Sin(nt)/n^2
 
Last edited:
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The equation is of the form
<br /> \frac{\mathrm{d}y}{\mathrm{d}t} = P(t)y(t) + Q(t)<br />
with
P(t)\equiv -1 and Q(t):=\sum_{n\ge 1}{\frac{\sin(nt)}{n^2}}. So, try with the formula
<br /> y(t) = \exp\left(\int{P(t)\mathrm{d}t}\right)\left(\int{Q(s)\exp\left(-\int{P(s)}\mathrm{d}s\right)\mathrm{d}s})\right) \biggr|_{s=t}<br />
 

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