General solution to a simple ODE

[brollysan]

Whenever I am stuck I usually manage by sitting down and working on the problem and eventuall finding the solution, this one is bothering me too much and I don't have any class until friday so no hope of finding out before then unless I ask here.

Q: Find a general solution to the diff.eq:

d[f(x)]/dx = bf(x). Given f(0) = 1 and f'(0) = 3 define constants and find a solution for f(x)


Attempts:
Stuck, used 2th order ODEs so much this thing confuses me.

 

[elibj123]

This is solved simply through separation of variables:

\frac{df}{dx}=bf

Therefore

\frac{df}{f}=bdx

Performing indefinite integration over this gives you:

ln(f)=bx+c

With c being arbitrary constant of integration
And explicitly f is given by

f(x)=ae^{bx}

Where I chose to rewrite the arbitrary constant e^c as a.

Determining a and b from your additional conditions is a simple algebric exercise.

 

[brollysan]

This is solved simply through separation of variables:

\frac{df}{dx}=bf

Therefore

\frac{df}{f}=bdx

Performing indefinite integration over this gives you:

ln(f)=bx+c

With c being arbitrary constant of integration
And explicitly f is given by

f(x)=ae^{bx}

Where I chose to rewrite the arbitrary constant e^c as a.

Determining a and b from your additional conditions is a simple algebric exercise.

Thank you!