Generational Similarities: Neutrino Connection?

alemsalem
Messages
173
Reaction score
5
they are in two different generations, but they would behave in the exact same way.
maybe we can tell from neutrinos?

Thanks!
 
Physics news on Phys.org


Most obvious analogy I can think of is the three quark colours. There's no experiment we can do that can tell us the actual colour of any specific quark at any given time. And yet, we were able to infer the existence of colours - ie there being three different types of each quark flavour - from experimental evidence such as that (a) without this additional quantum number, baryons would be symmetric in the interchange of any two quarks, in contravention of the Pauli principle, and (b) the branching ratios of reactions such as e+e- → hadrons would be three times too large as compared to those into eg muons.
 
Last edited:


(b) the branching ratios of reactions such as e+e- → hadrons would be three times too large as compared to those into eg muons.
Yes, this is the point. Universality of the weak interactions requires that the weak current is made up of equal parts from eνe, μνμ, etc. If e and μ could not otherwise be distinguished, the additional factor of two in the amplitude of any reaction that produced these particles would call our attention to the fact that there was two of them.
 


Thanks,, so for example beta decay would be happening at twice the rate?
is the extra factor of two compared to theory or other decays?
 


And of course, if it is a lighter mass, such as the one of the electron, you could consider chemistry.
 


arivero said:
And of course, if it is a lighter mass, such as the one of the electron, you could consider chemistry.
cool! it would also change the periodic table if we had two "electrons".
 
Last edited:
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Replies
2
Views
2K
Replies
11
Views
2K
Replies
11
Views
2K
Replies
33
Views
3K
Replies
4
Views
2K
Replies
4
Views
2K
Back
Top