Generator Equation: RPM & Power Relationship

  • Thread starter Thread starter mtanti
  • Start date Start date
  • Tags Tags
    Generator
Click For Summary
SUMMARY

The relationship between RPM and power in a generator is defined by the equation: output power = input power - losses = (2*pi/60)*RPM*T - losses. This equation illustrates that the RPM of a generator directly influences its output power, particularly in alternating current (A.C.) systems where maintaining a frequency of 60Hz is critical. Additionally, factors such as voltage, current, and impedance are essential for a comprehensive analysis of generator performance. Understanding these dynamics is crucial for optimizing generator efficiency and performance.

PREREQUISITES
  • Basic understanding of generator operation
  • Familiarity with alternating current (A.C.) systems
  • Knowledge of electrical impedance
  • Concept of torque in rotational systems
NEXT STEPS
  • Study the impact of impedance on generator efficiency
  • Learn about the relationship between torque and RPM in generators
  • Explore the effects of load variations on generator frequency
  • Investigate advanced generator control systems for maintaining optimal performance
USEFUL FOR

Electrical engineers, power system analysts, and anyone involved in generator design or optimization will benefit from this discussion.

mtanti
Messages
172
Reaction score
0
Does anyone know of an equation which relates RPM with power in a generator? It has to be for a general generator! :biggrin:
 
Engineering news on Phys.org
I am not sure (im still a newbe :frown: ), but let's work in senoidal regime:
Voltage v(t) = V . sin(wt+p)
w (omega) is in radians, so you could make w an equivalent to RPM:
1 RPM = 1 radian = 2*PI
Of curse, you will also need current and impedances for a deep analysis, but you can get the idea (P = (V^2)/Z)
I hope this is OK, sorry everyone if this is screwed up.
 
For alternating current (A.C.), the RPM of the generator determines the frequency of its output. In the U.S., power companies try to keep the frequency at 60Hz. When the load on the systems increases, the frequency tends to lower, so more power (steam flow through the turbin) is needed. The opposite happens when the load decreases.

Regards
Don
 
Well,

output power = input power - losses = wT - losses = (2*pi/60)*RPM*T -losses.

That's the most general equation I can think of without getting into reaction torque, inertia, etc.
 
Most likely this can only be answered by an "old timer". I am making measurements on an uA709 op amp (metal can). I would like to calculate the frequency rolloff curves (I can measure them). I assume the compensation is via the miller effect. To do the calculations I would need to know the gain of the transistors and the effective resistance seen at the compensation terminals, not including the values I put there. Anyone know those values?

Similar threads

  • · Replies 74 ·
3
Replies
74
Views
8K
  • · Replies 12 ·
Replies
12
Views
6K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 38 ·
2
Replies
38
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 0 ·
Replies
0
Views
1K
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K