Undergrad Generic Form of Hermitian Matrix

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The discussion revolves around the confusion regarding the generic form of a Hermitian matrix, specifically equation (2.5) in a referenced thesis. The participant questions why the bottom right element is denoted as ##\bar{A}## and how this relates to the commutation relation stated in equation (2.4). They express uncertainty about the connection between Hermiticity and the commutation relations, indicating a potential oversight in their understanding. An example is provided with a specific matrix, demonstrating that it can yield a Hermitian Hamiltonian. The conversation highlights the need for clarity on the interplay between matrix elements and commutation relations in Hermitian matrices.
thatboi
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I am reading the following thesis: https://www.kip.uni-heidelberg.de/Veroeffentlichungen/download/6387/pdf-6387.pdf
Specifically, I am confused about equation (2.5), where they give the generic form of the matrix ##\mathcal{M}## due to the Hermiticity of ##\mathcal{H}## and the commutation relation (2.4). I am confused about why the bottom right element is ##\bar{A}##. I'm sure this is related to the commutation relation but I'm confused as to how they enter into the picture. ##\mathcal{H}^{\dagger} = (\mathcal{M}a)^{\dagger}(a^{\dagger})^{\dagger} = a^{\dagger}\mathcal{M}^{\dagger}a## so where do the commutation relations come from or what step did I skip?
 
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Yes, something is missing, because I can take ##N=1## and ##M=\begin{pmatrix} 0&1\\1&2 \end{pmatrix}##, which make ##H=a^\dagger a^\dagger + aa+2aa^\dagger##, which is hermitian.
 
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