Undergrad Geodesics in 4D Spacetime: An Overview

Click For Summary
Geodesics in 4D spacetime are generalizations of straight lines in curved spaces, with straight lines characterizing flat spaces regardless of dimensionality. In a 4D spacetime, the geodesic can be defined using tangent vector components and the covariant derivative, specifically for inertial particles. The discussion emphasizes the importance of a solid understanding of special relativity and foundational concepts before tackling general relativity and geodesics. It is noted that the worldlines of non-inertial particles do not follow geodesics, while inertial frames have geodesic paths. A proper approach to learning involves studying relevant textbooks systematically and understanding the specific metrics of the spacetime in question.
Apashanka
Messages
427
Reaction score
15
The geodesic for 2-D, 3-D are straight lines.
For a 4-D spacetime (x1,x2,x3,t) what would be it's geodesic.??
The tangent vector components are ##V^0=\frac{∂t}{∂λ} , V^i=\frac{∂x^i}{∂λ},i=1,2,3## & ##(\nabla_V V)^\mu=(V^\nu \nabla_\nu V)^\mu=0,(\nu,\mu=0,1,2,3)##
 
Physics news on Phys.org
Geodesics are generalisations of straight lines to curved spaces. In any flat space they are going to be straight lines regardless of dimensionality.
 
Orodruin said:
Geodesics are generalisations of straight lines to curved spaces. In any flat space they are going to be straight lines regardless of dimensionality.
Sir one thing to clarify ,the curve traced by a particle in the 4-D space time in it's rest frame is a geodesic??
In rest frame ##x^\mu##={##\tau,constt##}
IMG_20190302_170516.jpg
 

Attachments

  • IMG_20190302_170516.jpg
    IMG_20190302_170516.jpg
    33.5 KB · Views: 554
Last edited:
Apashanka said:
the curve traced by a particle in the 4-D space time in it's rest frame is a geodesic??
Only if the particle is inertial. The worldlines of non-inertial particles are not geodesic. Also, the frame doesn’t matter
 
Apashanka said:
The geodesic for 2-D, 3-D are straight lines.
For a 4-D spacetime (x1,x2,x3,t) what would be it's geodesic.??
The tangent vector components are ##V^0=\frac{∂t}{∂λ} , V^i=\frac{∂x^i}{∂λ},i=1,2,3## & ##(\nabla_V V)^\mu=(V^\nu \nabla_\nu V)^\mu=0,(\nu,\mu=0,1,2,3)##

It's not clear from your posts that you are studying GR in any systematic way. Your questions show a lack of knowledge of basic concepts such as spacetime, coordinate systems, reference frames and the relationship between the physics you are trying to learn and the mathematics that underpins it.

In terms of geodesics, you should be developing your knowldege in a systematic way. You may approach the subject in many ways, but not all at the same time. For example, you might meet geodesics as solutions to the equations of motion for a given spacetime geometry. This could be developed from the Lagrangian principle of maximal proper time. Then, you might meet geodescics again in the light of the covariant derivative and more generally in terms of differential geometry and manifolds.

But, you can't dive in from all directions at once.

I'd also say that unless you have a rock-solid understanding of Special Relativity and other prerequisites - such as Lagrangian mechanics - you are largely wasting your time, as any knowledge you gain with your haphazard approach will be fragile and transient.

You must find yourself a reputable textbook and work though it systematically, taking time out as necessary to study the physics and mathematics that are prerequisites to the study of GR.
 
Dale said:
Only if the particle is inertial. The worldlines of non-inertial particles are not geodesic. Also, the frame doesn’t matter
That means the world lines of all inertial frames are geodesic irrespective of frame
 
Apashanka said:
That means the world lines of all inertial frames are geodesic irrespective of frame
There is no such thing as the world line of an inertial frame. I am sorry, but as has been pointed out already in this thread and others, you seem not to have the proper foundation to stand on to learn relativity at this moment in time. I would suggest that you work through the basics before attempting relativity.
 
  • Like
Likes weirdoguy
Apashanka said:
That means the world lines of all inertial frames are geodesic irrespective of frame
Frames don’t have worldlines. However, the integral curves of the tetrad of an inertial frame are all geodesics. Also, particles at rest in an inertial frame have geodesic worldlines
 
Last edited:
Apashanka said:
the 4-D space time

Which 4-D spacetime? You keep on using the term "the 4-D spacetime" as though there were only one. There are an infinite number of them. You need to specify which one.
 
  • Like
Likes Dale
  • #10
Apashanka said:
The geodesic for 2-D, 3-D are straight lines.
For a 4-D spacetime (x1,x2,x3,t) what would be it's geodesic.??
The tangent vector components are ##V^0=\frac{∂t}{∂λ} , V^i=\frac{∂x^i}{∂λ},i=1,2,3## & ##(\nabla_V V)^\mu=(V^\nu \nabla_\nu V)^\mu=0,(\nu,\mu=0,1,2,3)##

Step 1. Write down the geodesic equation - equation 56 in Carroll's treatment. Look it up.

What's the metric of the 4-d spacetime in question?
From the metric, compute the Christoffel symbols ##\Gamma^i{}_{jk}##

Can you solve the resulting equations?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
821
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
1K
  • · Replies 50 ·
2
Replies
50
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K