Geometric/algebraic proof of a quadratic

In summary, the conversation involves constructing an algebraic proof from a given drawing. The problem involves finding similar triangles and using their ratios to determine the lengths of certain lines. The key is to make constructions with Q'Q, PP', and 2, which are the only known lengths, and then equate the ratios of similar triangles to solve for QY and QX.
  • #1
raphael3d
45
0

Homework Statement



http://img717.imageshack.us/img717/4029/screenshot20110106at123.png

i don't know how to construct an algebraic proof from this or how to attempt it.

thank you

Homework Equations





The Attempt at a Solution

 
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  • #2
For an algebraic proof you can complete the square then solve for x.
 
  • #3
yes.

but i mean with the information from the drawing.

there are two similar triangles, therefore QN/2 = NY/QY. but how can one proceed here?
 
  • #4
or put it in another way, can't find more similar triangles. where is the next one?
 
  • #5
There are many similar triangles, such as OPP' with OQQ' and ONQ with OPM and OPN with OMQ where O is the circle center. But I don't know where to go from there yet.
 
  • #6
assuming that O is the center, which means ON=OQ=OM=QP=1, => NQ=PM=1.
but how can one deduce that the cutting point of P'Q' and PQ is the origin, is there some proof?
 
  • #7
How are you able to conclude that ON = OQ for example? In particular, I doubt that P'Q' hits the origin. This would only be true if (by similarity) PP' = QQ', and there doesn't seem to be any reason why that must happen.
 
  • #8
right. was a wrong assumption.

i guess the vital part is to make constructions with Q'Q,PP' and 2, the only known lengths and to equate the ratios of similar triangles to finally have QY=...,QX=...
 

1. How is a quadratic equation represented geometrically?

A quadratic equation can be represented geometrically as a parabola, which is a curved line that opens either upwards or downwards. The equation can also be represented by the coordinates of its vertex and the direction of its opening.

2. What is the difference between a geometric proof and an algebraic proof of a quadratic equation?

A geometric proof uses visual representations and properties of geometric shapes to prove a statement, while an algebraic proof uses algebraic manipulations and equations to prove the statement.

3. How can the geometric properties of a parabola be used to prove a quadratic equation?

The distance between the vertex of a parabola and its focus point is equal to the distance between the vertex and the directrix line. This property can be used to prove the vertex form of a quadratic equation.

4. Can a quadratic equation be proven using both geometric and algebraic methods?

Yes, a quadratic equation can be proven using both geometric and algebraic methods. The geometric properties of a parabola can be used to establish the relationship between the vertex, focus, and directrix, while algebraic manipulations can be used to solve for the coefficients in the equation.

5. Why is it important to understand both geometric and algebraic proofs of a quadratic equation?

Understanding both geometric and algebraic proofs of a quadratic equation allows for a deeper understanding of the properties and relationships involved. It also provides multiple ways to approach and solve problems related to quadratic equations, making it a useful skill in various fields of mathematics and science.

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