Geometric and arithmetic series

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SUMMARY

The discussion focuses on solving a problem involving arithmetic and geometric progressions where the terms a, b, and c are specified as the fifth, seventh, and thirty-seventh members of both sequences. The equation derived is 12r^32 - 32r^12 + 20=0, where r represents the common ratio in the geometric series. Participants suggest representing the terms using symbols for the first term and common difference of the arithmetic progression and the first term and common ratio of the geometric progression to simplify the expression a^{b-c}b^{c-a}c^{a-b} effectively.

PREREQUISITES
  • Understanding of arithmetic progression (A.P.) and geometric progression (G.P.)
  • Knowledge of algebraic manipulation and laws of exponents
  • Familiarity with solving polynomial equations
  • Ability to represent terms in sequences using symbols
NEXT STEPS
  • Study the properties of arithmetic and geometric progressions in detail
  • Learn how to solve polynomial equations, specifically cubic equations
  • Explore the concept of arithmetico-geometric series and its applications
  • Practice problems involving the manipulation of expressions with exponents
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Students studying mathematics, particularly those focusing on sequences and series, educators teaching algebra concepts, and anyone interested in solving complex polynomial equations.

Government$
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Homework Statement


If a,b,c, are at the same time fifth, seventh and thirty seventh member of arithmetic and geometric progression then a^{b-c}b^{c-a}c^{a-b} is:

The Attempt at a Solution



I tried solving system of equations but i have four unknown. I was able to reduce it to on unknown.

12r^32 - 32r^12 + 20=0 where r is common ration in geometric series. I have no idea how to solve this. :cry:

Maybe trying to solve the system isn't a way to go?
 
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Wel its evident that two solutions are 1 and - 1 but what kind of geometric progression is with r=1 or r=-1?
 
Government$ said:

Homework Statement


If a,b,c, are at the same time fifth, seventh and thirty seventh member of arithmetic and geometric progression then a^{b-c}b^{c-a}c^{a-b} is:

The Attempt at a Solution



I tried solving system of equations but i have four unknown. I was able to reduce it to on unknown.

12r^32 - 32r^12 + 20=0 where r is common ration in geometric series. I have no idea how to solve this. :cry:

Maybe trying to solve the system isn't a way to go?
Hello Government$
Do you mean that a,b,and c are parts of an arithemtico-geometric sequence(As in saying that they can be represented as the product of corresponding terms of an arithmetic and geometric series) or implying that there exist separate (not to be sure) arithmetic and geometric progressions satisfying the condition?
Regards
Yukoel
 
Last edited:
As i have understood it there exist separate arithmetic and separate geometric progression. This is a first time i hear of arithemtico-geometric series.
 
Government$ said:
As i have understood it there exist separate arithmetic and separate geometric progression. This is a first time i hear of arithemtico-geometric series.
Hello,
Thanks for clarifying this. Well the way I can think of it is doesn't utilize finding the common difference and /or common ratio .Try writing them separately as nth(n=5,7,and 37 as given) terms of the Geometric and arithmetic sequence (Don't be disheartened by the number of unknowns :) ).Now look at the expression .In order to simplify it you might want to multiply the bases easily, by which sequence would you represent it(I mean a,b and c)? If you have had multiplied you might need to easily add the exponents. Which sequence's use makes it easier?
Regards
Yukoel
 
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Government$ said:

Homework Statement


If a,b,c, are at the same time fifth, seventh and thirty seventh member of arithmetic and geometric progression then a^{b-c}b^{c-a}c^{a-b} is:

The Attempt at a Solution



I tried solving system of equations but i have four unknown. I was able to reduce it to on unknown.

12r^32 - 32r^12 + 20=0 where r is common ration in geometric series. I have no idea how to solve this. :cry:

Maybe trying to solve the system isn't a way to go?

This is a simple problem. You're told that a,b,c are particular terms of an arithmetic progression (A.P.) and a geometric progression (G.P.). So just use symbols to represent the first term and common difference of that A.P. and the first term and common ratio of the G.P. and express a,b,c both ways.

You're asked to evaluate an expression that's the product of powers of a, b and c. For the bases (e.g. a or b), use the G.P. representation. For the exponents (e.g. b-c), use the A.P. representation. Do the algebra using the laws of exponents and you'll be pleasantly surprised at what cancels out.
 

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