Geometrical Optics (lens and refraction)

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songoku
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Homework Statement


1. A cylindrical tank 2.4 m deep is full to the brim with water. Sunlight first hits part of the tahnk bottom when the rising maes at 22o angle with the horizon. Find the tank's diameter


2. An aquarium is made from a thin-walled tube of transparent plastic 50 cm in diameter. If we are looking directly into th aquarium, what is the apparent distance to a fish 15 cm from the aquarium wall?

Homework Equations


n = c / v

n1sin i = n2 sin r

n = real depth / apparent depth


The Attempt at a Solution


1. I can't imagine the situation and I don't understand this part :"Sunlight first hits part of the tank bottom when the rising makes at 22o angle with the horizon."

2. The shape of the aquarium is cylindrical? I don't know what the diameter is used for.

Please help. Thanks
 
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rude man said:
I'm befuddled too. The poser seems to have ESL.
What is ESL?
In part B are we looking "directly" thru the wall or from atop the aquarium?

That's also the thing that I don't know. But let us take both cases:
a. we are looking from the top of aquarium --> we don't know the real depth so how can we find the apparent depth

b. we are looking directly through the wall --> no idea how to do it
 
songoku said:
What is ESL?
English as Second Language.

That's also the thing that I don't know. But let us take both cases:
a. we are looking from the top of aquarium --> we don't know the real depth so how can we find the apparent depth

b. we are looking directly through the wall --> no idea how to do it

Me neither. Don't understand the question at all.
 
Sunlight refracted to just reach the bottom of the tank.
 

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Basic_Physics said:
Sunlight refracted to just reach the bottom of the tank.

Oh it is actually pretty easy. Just use the snell's law to find the angle of refraction and use tan to find the diameter.

Can you help me with the second one too?

Thanks
 
Fish in tank

Refraction at the wall of the tank.
The apparent depth decreases due to the refraction of the light at the water-air interface.
 

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Basic_Physics said:
Refraction at the wall of the tank.
The apparent depth decreases due to the refraction of the light at the water-air interface.

Thanks a lot for your help :smile: