Geometry Problem: ∠EDB in Triangle ABC

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Homework Help Overview

The problem involves triangle ABC with specific angle measures and additional lines intersecting at points D and E. The goal is to determine the measure of angle EDB based on the given conditions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of coordinate geometry versus simple geometry for solving the problem. There are requests for diagrams and markings of angles and distances. Some participants suggest finding angles at intersection points and exploring relationships between angles.

Discussion Status

The discussion is ongoing with various approaches being explored. Participants have shared diagrams and are questioning the relationships between angles. Some guidance has been offered regarding drawing parallels and extending lines, but no consensus or clear solution has emerged yet.

Contextual Notes

There are indications of isosceles triangles and specific angle measures that may influence the problem's complexity. Participants express uncertainty about the implications of the given angles and the overall geometric configuration.

projjal
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Homework Statement



Suppose ABC is a triangle, where ∠ABC = ∠ACB =80°. A line BD through B meets AC at D such that
∠DBC=60°.Similarly CE meets AB at E where ∠ECB = 50°. Whats the value of ∠EDB?

Homework Equations





The Attempt at a Solution


I solved the problem using coordinate geometry but i was asked to solve it using simple geometry.
 
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hi projjal! :wink:
projjal said:
… i was asked to solve it using simple geometry.

show us your diagram, with all angles marked, and all equal distances marked :smile:
 
sorry for that. i have uploaded the diagram.
 

Attachments

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Let's denote the intersection of EC and BD by F. Can you find the angles at this point F?

Can you find the angle at A?
 
projjal said:
i have uploaded the diagram.

mark all the angles, and all equal distances

(and preferably re-draw it so that those 80° angles look like 80°)
 
preferably re-draw it so that those 80° angles look like 80°
I think now it should be okay with the diagrams.I have also marked all the angles.
here also AB=AC & AD=BD
now what's EDB ?
 

Attachments

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ah , that's much better! :smile:
projjal said:
here also AB=AC & AD=BD

also BE = BC :wink:

hmm … i can't see any obvious way to find EDB :redface:

(longshot: i wonder whether it has anything to do with 40° being twice 20° ?)
 
Draw a line in D parallel to BC.
 
If you extend DE and CB until they meet at a point P, can you find angle EPB?
 
  • #10
If you extend DE and CB until they meet at a point P, can you find angle EPB? .
I have already tried that but i couldnot find the answer.
 
  • #11
micromass said:
Draw a line in D parallel to BC.

I couldnot get anything from that.If you could do it please specify it to me.
 
  • #12
EPDF form a quadrilateral, the other 3 angles are known.
 
  • #13
MrAnchovy said:
EPDF form a quadrilateral, the other 3 angles are known.

If P is the point of intersection of DE & CB how EPDF forms a quadrilateral?
 
  • #14
projjal said:
If P is the point of intersection of DE & CB how EPDF forms a quadrilateral?

Sorry, EPBF - not enough screen area to see the diagram and type at the same time!
 
  • #15
MrAnchovy said:
Sorry, EPBF - not enough screen area to see the diagram and type at the same time!
We know PBF and BFE. What's the third?
I don't think it's going to be that simple anyway. Seems to me these angles have been chosen quite carefully. It's no coincidence that there are isosceles triangles all over the place which would not be so if we were to change just one of the given angles.
 
  • #17
So that's how its done.
 
  • #18
haruspex said:
We know PBF and BFE. What's the third?

Oops, clearly not a good idea for me to try and do geometry in my head. I see the solution is not trivial.
 

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