Geostationary Satelite Problem

In summary, the task is to put a satellite into a circular orbit around Venus so that it stays above one spot on the surface, orbiting Venus once each Venus day. To determine the distance from the center of the planet to place the satellite, two equations are needed: v=2(pie)r/T and equating gravitational force to centripetal force. The period of the orbit is 2802 hours. By solving for r using the two equations with two unknowns, the distance from the center of the planet to place the satellite can be determined.
  • #1
Jtappan
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Homework Statement



Venus has a mass of about 4.87 1024 kg. The length of a day on Venus is 2802 hrs. Your task is to put a satellite into a circular orbit around Venus so that it stays above one spot on the surface, orbiting Venus once each Venus day. At what distance from the center of the planet should you place the satellite?
_____ m



Homework Equations



v = 2(pie)r/T where T = the period ? that is one equation

The Attempt at a Solution



Do you use the period of venus to calculate the acceleration and speed of the planet? What do you do with the mass of venus?
 
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  • #2
Yes, the period gives you the rotation speed. Keep in mind that there is a relationship between rotational speed and tangential velocity.

Once you have the velocity, think about what will keep the satellite in place: Gravity.
 
  • #3
what is the relationship between rotational speed and tangential velocity?
 
  • #4
Jtappan said:
what is the relationship between rotational speed and tangential velocity?

The period of the orbit = 2802 hrs

v = 2(pie)r/T... here T = 2802 converted to the appropriate units...

also, equate the gravitational force to the centripetal force... that gives a second equation in terms of v and r...

2 equations with 2 unknowns, v and r. solve for r
 

1. What is a geostationary satellite?

A geostationary satellite is a man-made object that is placed in a specific orbit around the Earth. It orbits the Earth at the same rate as the Earth rotates, allowing it to appear stationary from the ground.

2. What is the "Geostationary Satellite Problem"?

The "Geostationary Satellite Problem" refers to the limited number of orbital slots available for geostationary satellites. These slots are highly sought after because of the advantages of having a satellite appear stationary in the sky.

3. How many geostationary satellites are currently in orbit?

As of January 2021, there are over 500 geostationary satellites in orbit. However, only a fraction of these are active as many are retired or have failed.

4. How is the "Geostationary Satellite Problem" being addressed?

The "Geostationary Satellite Problem" is being addressed through international coordination and regulations. Organizations such as the International Telecommunication Union (ITU) allocate orbital slots to countries and companies to ensure fair use of the limited resource.

5. What are the potential consequences of not addressing the "Geostationary Satellite Problem"?

If the "Geostationary Satellite Problem" is not addressed, there is a risk of overcrowding in the geostationary orbit. This could lead to interference between satellites and potentially impact their functionality. It could also limit the future use and development of geostationary satellites for communication, weather monitoring, and other important applications.

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