Getting a rhombus vertex from one vertex and its area

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Homework Help Overview

The problem involves finding the coordinates of the remaining vertices of a rhombus given one vertex and the area. The vertex A(-1,8) is known, and the minor diagonal is situated on a specified line. The area of the rhombus is given as 30.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between the known vertex and the lines defining the diagonals of the rhombus. There are attempts to derive the second diagonal's line and questions about the intersection points. Some participants express uncertainty about the relevance of the midpoint of the rhombus and how to find it without fully determining the second diagonal.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the problem. Some hints have been provided regarding the midpoint of the rhombus and the relationship between the lines, but no consensus or resolution has been reached yet.

Contextual Notes

There is a noted uncertainty about whether point A belongs to the line L, which may affect the approach to finding the other vertices. Participants are also considering the implications of the area constraint on their reasoning.

Telemachus
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Hi there. I am tryin to solve this one, I know that if I find the way to get one more vertex i'd have it solved.

Homework Statement


The point A(-1,8) is the vertex of a rhombus which minor diagonal is situated on the line L: L=\begin{Bmatrix} x=3\mu &amp; \mbox{ }&amp; \\y=1+4\mu &amp; \mbox{}&amp;\end{matrix}<br />, \mu\in{R}. Get the coordinates of the rest of the vertex knowing that the rhombus area is 30.

Homework Equations


A=\displaystyle\frac{dD}{2}

The Attempt at a Solution


Well, I haven't done too much. Actually I did some, but then I realized that I had confused something, cause I got the line L' where would be located the major D, but I've used for it the point A, and then I was trying to get the point of intersection between L and L', so then I doubled it, and I was going to get my second vertex, but then I realized that it was wrong, cause I couln't use point A, cause A don't belongs to L', it belongs to L, so...

30=\displaystyle\frac{dD}{2}\Rightarrow{60=dD}

So, I don't know much about L', but that its perpendicular to L.

L&#039;=\begin{Bmatrix} x=x_0+4/3\lambda &amp; \mbox{ }&amp; \\y=y_0-\lambda &amp; \mbox{}&amp;\end{matrix}<br />
 
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Hi Telemachus! :smile:
Telemachus said:
So, I don't know much about L', but that its perpendicular to L.

That's right :smile:, but from then on you're making it too complicated. :redface:

Hint: Where is the midpoint of the rhombus? :wink:
 
On the intersection between L and L', but how should I get L'? I thought maybe using pythagoric equation I could find another vertex, but I am not too sure. I know it gives enough data, but I don't know how to use it.
 
I had a misunderstood, I think I was on the right way, cause actually I didn't corroborate if A belongs to L, and the sentence don't say so. I'll corroborate, if it doesn't I was on the right way, and it will be easy to solve, cause if A don't belongs to L, it must belongs to L'.

Bye there, and thanks.
 
Telemachus said:
On the intersection between L and L', but how should I get L'?

L' is perpendicular to L, and goes through A. :smile:

(and remember, you don't need to find L', you only need the midpoint :wink:)
 
How could I get the midpoint without L'? I thought of it as the intersection between L and L'.
 
AM is on L', so it's perpendicular to L. :wink:
 

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