Why does my method for calculating this value from...?

  • Thread starter Thread starter Rijad Hadzic
  • Start date Start date
  • Tags Tags
    Method Value
Click For Summary

Homework Help Overview

The discussion revolves around calculating the distance from the centroid of an equilateral triangle to the midpoint of one of its sides. The original poster attempts to use the Pythagorean theorem after bisecting the triangle, but encounters a discrepancy with the solution presented in their textbook.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore different definitions of the triangle's center, particularly the centroid versus the midpoint of a side. There are discussions about the geometric properties of the triangle and the implications of cutting the triangle in half.

Discussion Status

Some participants provide clarifications regarding the definition of the triangle's center, indicating that the centroid is not the same as the midpoint of the line created by bisecting the triangle. There is an ongoing exploration of the relationships between the sides and angles of the triangle, as well as the implications of the original poster's method.

Contextual Notes

There is a noted difference between the original poster's method and the textbook's approach, leading to confusion about the correct interpretation of the problem. The discussion includes references to geometric properties and relationships that are not fully resolved.

Rijad Hadzic
Messages
321
Reaction score
20

Homework Statement


So I have an equilateral triangle of side(s) = 3x10^-2 m

Im trying to find the value of the distance from a point directly in the middle of the triangle, to the middle of one side.

Homework Equations

The Attempt at a Solution


What I wanted to do was, cut the triangle in half, so now I have a hypotenus, of value 3x10^-2 m, a base of half of that, 1.5x10^-2 m, and a side b which I use pythagoras to solve for.

b = ((3x10^-2)^2 - (1.5x10^-2)^2 ) ^1/2

which = .02598,

and now taking half of that I have the value of the distance from a point directly in the middle of the triangle, to the middle of one side.

But my book tells me I am wrong.

What they did was construct a line from one vertex of the triangle to the middle, then adjacent to that is a line l/2, and then there is another line which I'm trying to solve for, going from the middle of one side to the origin. They then used tan(30) l/2 to calculate it to .0086...

but I don't get why my method works. I'm essentially halfing the equalateral, finding the long side, and taking half of it, how doesn't that give me the value of the distance from a point directly in the middle of the triangle, to the middle of one side
 
Physics news on Phys.org
Your definition of center of the triangle is not the same as the book (and what most people consider). Here, it is the center of mass, is essentially what you want to find. If you think about how you cut the triangle into two right triangles, the center of mass will lie on that line where you made the cut, but it will not be the midpoint of that line.
You need to find the point where the area above the point is equal to the area below that point.
 
The centre of the equilateral triangle is at equal distance from all corners of the triangle. In the figure, it is denoted by s. You need to find the distance d.
upload_2017-10-28_7-27-34.png
 

Attachments

  • upload_2017-10-28_7-27-34.png
    upload_2017-10-28_7-27-34.png
    1.8 KB · Views: 876
  • Like
Likes   Reactions: scottdave
ehild said:
The centre of the equilateral triangle is at equal distance from all corners of the triangle. In the figure, it is denoted by s. You need to find the distance d.
View attachment 213893
I see. So d isn't = to (1/2) s+d, right?
 
Rijad Hadzic said:
I see. So d isn't = to (1/2) s+d, right?
No. d=(1/2)s +d means 0=(1/2)s which is false.
What is the blue angle in the yellow triangle? what is the ratio d/s?
upload_2017-10-29_5-41-24.png
 

Attachments

  • upload_2017-10-29_5-41-24.png
    upload_2017-10-29_5-41-24.png
    1.9 KB · Views: 374
ehild said:
d=(1/2)s +d means 0=(1/2)s
At a guess, Rijad meant d=(½)(s+d), but still false.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
4K
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 14 ·
Replies
14
Views
1K
Replies
11
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K