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Getting Qideal from Bernouli and continuity

  1. Apr 22, 2013 #1
    So, I found a paper relating to a lab report that I've been working on that says that I can get
    Qideal=(pi*d^2)/4) √((2ΔP/(ρ(1-D/D')^4 ))
    From Bernouli which my book has as:
    P11+1/2v1^2+gh1=P22+(1/2)v2^2+gh2

    and Continuity which my book has as:
    ρ1A1V1 = ρ2A2V2

    I'm able to get kind of in that direction applying this,
    ΔP = -ρgΔh

    And the area portion makes sense logically

    But I'm wondering what I'm missing.
    Thanks!
     
  2. jcsd
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