# Getting Qideal from Bernouli and continuity

#### Sheogoroth

So, I found a paper relating to a lab report that I've been working on that says that I can get
Qideal=(pi*d^2)/4) √((2ΔP/(ρ(1-D/D')^4 ))
From Bernouli which my book has as:
P11+1/2v1^2+gh1=P22+(1/2)v2^2+gh2

and Continuity which my book has as:
ρ1A1V1 = ρ2A2V2

I'm able to get kind of in that direction applying this,
ΔP = -ρgΔh

And the area portion makes sense logically

But I'm wondering what I'm missing.
Thanks!

Related Mechanical Engineering News on Phys.org

#### Chestermiller

Mentor
The OP seems to be citing a relationship for calculating the volumetric flow rate across a resistance in the flow, such as an orifice plate based on the pressure difference across the resistance.

"Getting Qideal from Bernouli and continuity"

### Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving