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## Homework Statement

Water flows through a horizontal tapered pipe. At the wide end its speed is 4.0 m/s and at the narrow end it is 5.0 m/s. The pressure in the wide pipe is 2.5 x 10^5 Pa. What is the pressure in the narrow pipe?

a. 2.5 x 10^2 Pa

b. 3.4 x 10^3 Pa

c. 4.5 x 10^3 Pa

d. 2.3 x 10^5 Pa

e. 8.0 x 10^5 Pa

## Homework Equations

P1+1/2*ρ*v1

^{2}= P2+1/2*ρ*v2

^{2}

A1*v1=A2*v2

## The Attempt at a Solution

1-wide

2-narrow

P1+1/2*ρ*v1

^{2}= P2+1/2*ρ*v2

^{2}

2.5 x 10^5 Pa + 1/2*1000kg/m

^{3}*(4m/s)

^{2}=P2 + 1/2*1000kg/m

^{3}*(5m/s)

^{2}

2.5 x 10^5 Pa + 1/2*1000kg/m

^{3}*(4m/s)

^{2}- 1/2*1000kg/m

^{3}*(5m/s)

^{2}=P

2.5 x 10^5 Pa + 1/2*1000kg/m

^{3}*[(4m/s)

^{2}-(5m/s)

^{2}]=P

2.455x10^5 Pa=P

the answer is not in the options :s can someone tell me what i did wrong?

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