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**[SOLVED] Giant Swing, Uniform Circular Motion**

## Homework Statement

The "Giant Swing" at a county fair consists of a vertical central shaft with a number of horizontal arms attached at its upper end. Each arm supports a seat suspended from a cable 5.00 long, the upper end of the cable being fastened to the arm at a point 3.00 from the central shaft.

A) Find the time of one revolution of the swing if the cable supporting a seat makes an angle of with the vertical.

B) Does the angle depend on the weight of the passenger for a given rate of revolution?

## Homework Equations

R = Lsin(\theta)

v = [tex]\sqrt{gtan(\theta)R}[/tex]

T = 2[tex]\Pi[/tex]R/v

## The Attempt at a Solution

tried using L = 3+5m*sin([tex]\theta[/tex])) to get 4m

R then equals = 2m

v then equals = [tex]\sqrt{9.8*2*tan\theta}[/tex] = 11.3m/s

T then equals 2[tex]\Pi[/tex](2m)/11.3m/s = 1.1s wrong

I tried a few other combinations where I used 3+(5sintheta) as the L and got T=4.4s which was wrong as well.

I'm not sure what I'm doing wrong, I think I have the correct equations and I know I have the right angle and distances, I guess I'm just not sure how to derive the right length and and radius.

I'm also thinking that for part B the weight will determine the angle that the seat swings, but I don't want to risk losing the only chance I have on that part of the problem (masteringphysics).

any and all help is greatly appreciated.

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