Gibbs Phenomenon: Investigating Fourier Series of a Discontinuity

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SUMMARY

The discussion focuses on the Gibbs phenomenon as it relates to the Fourier series of the function \( f(x) = \text{sgn}(x) \) over the interval \([-π, π]\). Participants clarify that since \( f \) is an odd function, it is sufficient to analyze its behavior on the interval \([0, π]\). The Gibbs phenomenon describes the overshoot that occurs near discontinuities in the Fourier series representation of such functions. References to Wolfram MathWorld provide additional context and resources for understanding this phenomenon.

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mathmari
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Hey! :o

I am looking at the Gibbs phenomenon.
We want to look at the behaviour of a Fourier series of a region of discontinuity of $f$, especially we are looking at the function $f(x)=sgn(x), x \in [-\pi, \pi]$ near $0$.Since $f$ is odd, it suffices to look its behaviour at $[0, \pi]$.

Why does the last sentence stand?? (Wondering)
 
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mathmari said:
Hey! :o

I am looking at the Gibbs phenomenon.
We want to look at the behaviour of a Fourier series of a region of discontinuity of $f$, especially we are looking at the function $f(x)=sgn(x), x \in [-\pi, \pi]$ near $0$.Since $f$ is odd, it suffices to look its behaviour at $[0, \pi]$.

Why does the last sentence stand?? (Wondering)

A function is 'odd' if is $\displaystyle f(x) = - f(- x)$, so that is $f(0)=0$. Regarding the Gibbs phenomenon see...

Gibbs Phenomenon -- from Wolfram MathWorld

Kind regards

$\chi$ $\sigma$
 
chisigma said:
A function is 'odd' if is $\displaystyle f(x) = - f(- x)$, so that is $f(0)=0$. Regarding the Gibbs phenomenon see...

Gibbs Phenomenon -- from Wolfram MathWorld

Kind regards

$\chi$ $\sigma$

And why is it sufficient to look at the half of the interval, $[0, \pi]$ ? (Wondering)
 

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