Given Cont.Joint PDF function find Covariance MATRIX

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The discussion focuses on calculating the covariance matrix for the joint probability density function (PDF) defined as fx(x1,x2,x3)=2/3(x1+x2+x3) over the domain 0 PREREQUISITES

  • Understanding of joint probability density functions
  • Knowledge of expected values and variance calculations
  • Familiarity with covariance concepts
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  • Study the calculation of expected values for multivariate distributions
  • Learn about variance and covariance in the context of joint distributions
  • Explore the properties of covariance matrices in multivariate statistics
  • Investigate the implications of symmetry in joint PDFs
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Statisticians, data analysts, and students in quantitative fields who are working with multivariate distributions and need to compute covariance matrices for joint probability density functions.

circuitman
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Hello Buddies,

I need to calculate "covariance matrix" of the given joint PDF function.

Joint PDF is fx(x1,x2,x3)=2/3(x1+x2+x3)

over S (x1,x2,x3), 0<xi<1, i=1,2,3

How can I calculte the Covariance Matrix?

Thanks
 
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There's a lot of symmetry to exploit here. Here is an outline of the brute force approach.

Step 1: Find [tex]E(X_1)[/tex]. What will that tell you about the other 2 means.

Step 2: Find [tex]E(X_1^2)[/tex], from this and Step 1 you can get [itex]\sigma_{X_1}^2[/itex] (again - what about the other two?)

Step 3: Now get the covariances between [itex]X_1[/itex] and [itex]X_2[/itex] and [itex]X_1[/itex] and [itex]X_3[/itex].

Once you have these things you can assemble the covariance matrix.

By the way: I'm assuming you meant that

[tex] f(x_1, x_2, x_3) = \frac 2 3 \left(x_1 + x_2 + x_3\right), \quad 0 < x_1, x_2, x_3 < 1[/tex]

rather than something like

[tex] \frac{2}{3(x_1 + x_2 + x_3)}, \quad 0<x_1, x_2, x_3 < 1[/tex]

since the second version isn't a density function.
 

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