Given speed/mass find R (centripetal)

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The discussion revolves around calculating the radius of a hump based on the centripetal force experienced by a driver in a car. For a 50kg person driving at 8.3m/s, the radius of the hump was determined to be 9.93 meters using the formula R = (mv²)/(mg - FN). Additionally, to achieve a sensation of weightlessness at the top of the hump, the car must travel at a speed of 9.86 m/s, derived from the equation v = (gR)^(0.5). The calculations for both the radius and the speed were confirmed to be correct. The thread highlights the application of centripetal force equations in real-world scenarios.
jybe
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Homework Statement


1) A 50kg person drives a car at 8.3m/s over a hump in the road. At the top of the hump, the driver feels a force of 143 N from the seat. What is the radius of the hump?

2) At what speed will the car need to move over the hump for the person to feel weightless at the top?

Homework Equations


Fc = (mv2)R

The Attempt at a Solution


1)

Fc = mac
mg - FN = (mv2)/R
R = (mv2)/(mg - FN)
R = 9.93 m

2)

g = v2/R (total centripetal acceleration must be equal to gravity)
v = (gR)0.5
v = 9.86 m/s

Pretty sure #2 is right, but did I get the correct radius in #1?
 
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jybe said:
did I get the correct radius in #1?
Yes, you did.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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