Glancing Collisions In 2D, help simplifying

  • Thread starter Visionary_
  • Start date
  • #1

Homework Statement


We are only given variables in this problem, that is:
m1 travels at V, collides with 2m which is at rest
results in m going off at 45° at V1
2m also goes off at 45° down at V2
Calculate V1 and V2 in terms of V


Homework Equations


Ʃρx-initial=Ʃρx-final
Ʃρy-initial=Ʃρy-final
Use Linear combinations; sin45= √2/2=cos45

The Attempt at a Solution


x direction:
mv1=mv1√2/2+2mv√2/2
y direction
0=√2/2(mv1+2mv)
 

Answers and Replies

  • #2
PeterO
Homework Helper
2,426
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Homework Statement


We are only given variables in this problem, that is:
m1 travels at V, collides with 2m which is at rest
results in m going off at 45° at V1
2m also goes off at 45° down at V2
Calculate V1 and V2 in terms of V


Homework Equations


Ʃρx-initial=Ʃρx-final
Ʃρy-initial=Ʃρy-final
Use Linear combinations; sin45= √2/2=cos45

The Attempt at a Solution


x direction:
mv1=mv1√2/2+2mv√2/2
y direction
0=√2/2(mv1+2mv)
The equations you have written out are not quite right.

You have:

x direction:
mv1=mv1√2/2+2mv√2/2
y direction
0=√2/2(mv1+2mv)

but were perhaps trying for

x direction:
m1V=m1V1√2/2+m2V2√2/2
y direction
0=√2/2(m1V1+m2V2)

Though perhaps you really did mean masses m and 2m ?
 
  • #3
yes the second mass was 2m as in twice the mass,
i simplified the problem further and got a 90% on the paper so its fine :)
 

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