I'm a novice in SUSY and I'v got a question concerning spontaneous supersymmetry breaking and goldstinos. In Martin's review on page 68 there is a proof of a statement about existence of massless particle when one of ##F_i##'s or ##D_a##'s VEV is not zero. The thing I don't get is why vector ##\tilde{G}## is proportional to goldstino wave function. I guess that it means that after diagonalization of ##m_F## there is a field ##\Psi = \sum F_i \, \Psi_i + \sum D_a \, \lambda_a##, that corresponds to zero eigenvalue of ##m_F##. Is it correct? If so, could you please give any hints of proof of this statement.(adsbygoogle = window.adsbygoogle || []).push({});

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# Goldstino field

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