Golf ball equation for Projectile Motion need to know if I am doing it correctly

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SUMMARY

The discussion focuses on calculating the projectile motion of a golf ball hit at an initial speed of 109 km/h. Key calculations include converting the speed to meters per second, determining the longest possible hole-in-one distance, the time the ball remains airborne, and the maximum height achieved. The gravitational constant used is -9.8 m/s², with a suggestion to use -9.81 m/s² for more accuracy. The calculations involve trigonometric functions and basic kinematic equations.

PREREQUISITES
  • Understanding of projectile motion principles
  • Knowledge of kinematic equations
  • Ability to convert units (km/h to m/s)
  • Familiarity with trigonometric functions (e.g., cosine)
NEXT STEPS
  • Learn how to convert units from kilometers per hour to meters per second
  • Study the equations of motion for projectile trajectories
  • Explore the effects of different launch angles on projectile distance
  • Investigate the impact of air resistance on projectile motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for practical examples to illustrate these concepts.

sophiegirl411
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Homework Statement



A golfer hits the ball with an initial speed of 109km/hr
A) What is the longest hole in one (in km) that he golfer can make without the ball rolling?
B)How much time does the ball spend in the air
C) What is the maximum height reached by the ball

Homework Equations



gravity= -9.8 m/s

The Attempt at a Solution


109cos(45)=77.1 km/hr
t=77.1/g
9.8m/s *1/1000m *3600^2=127008
 
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sophiegirl411 said:

Homework Statement



A golfer hits the ball with an initial speed of 109km/hr
A) What is the longest hole in one (in km) that he golfer can make without the ball rolling?
B)How much time does the ball spend in the air
C) What is the maximum height reached by the ball

Homework Equations



gravity= -9.8 m/s

The Attempt at a Solution


109cos(45)=77.1 km/hr
t=77.1/g
9.8m/s *1/1000m *3600^2=127008

If g = 9.81, you need to change 109 km/h into metres per second
 

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