Grade 10 Physics: Displacement of Speedboat

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SUMMARY

The displacement of a speedboat traveling at 6.0 m/s [E] for 90 seconds, followed by a uniform acceleration of 2.0 m/s² [E] for 5 seconds, can be calculated using the formula ΔD = V1 * ΔT + 1/2 * A * (ΔT)². The total time for the calculation is the sum of both segments, totaling 95 seconds. The first segment involves constant speed, while the second segment involves acceleration, requiring separate calculations for each phase before summing the displacements.

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Homework Statement


ok here's the question

A speed boat travels at 6.0 m/s [E] for 90s and then accelerates uniformly at 2.0 m/s² [E] for 5.0s. Caculate the displacement of the speedboat


Homework Equations


is this the formula i am suppose to use for this question?

Delta D= V1*Delta T+1/2*A(Delta T)²

note that the a in that formula is suppose to be vector acceleration.

for the time do i just add up 90 seconds and 5 seconds?
 
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HelloMotto said:

Homework Statement


ok here's the question

A speed boat travels at 6.0 m/s [E] for 90s and then accelerates uniformly at 2.0 m/s² [E] for 5.0s. Caculate the displacement of the speedboat


Homework Equations


is this the formula i am suppose to use for this question?

Delta D= V1*Delta T+1/2*A(Delta T)²

note that the a in that formula is suppose to be vector acceleration.

for the time do i just add up 90 seconds and 5 seconds?
No, you should look at the question in 2 parts, the first being the displacement over the first 90 seconds at constant speed (no acceleration), and the second part being the displacement over the next 5 seconds at the given acceleration and initial speed. Then add 'em up. You can't do it all at once, since the acceleartions are different over the noted time periods.
 

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